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3 years ago

Find the four smallest elements of the set

Mathematics

1 answer:

Georgia [21]3 years ago

7 0

Answer:

The element has a smallest part to it, which is an atom

Since everything has a small part to it, you can predict that their are types of charges.

An atom has several charges, not smaller parts to it.

Atoms charges can be electron, neutron and proton.

Step-by-step explanation:

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Write a first step question and answer.Then solve the problem.The store owner gets a shipment of 7 boxes of games.There are 6 ga

n200080 [17]

(7 x 6) - 18 = 24 games left

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4 years ago

Read 2 more answers

Help i dont understand Pls help :(

olya-2409 [2.1K]

Answer:

x = 1?

Step-by-step explanation:

I think functions are basically just variables but extra so they both act the same. I'm not 100% sure but I Think

if f(x) = -5x + 1 when f(x) = 6,

replace f(x) with 6 so,

6 = 5x + 1

1 - 6 = 5x + 1 - 1

(subtract one on both sides to isolate the variable)

5 = 5x

5/5 = 5x/5

(to Actually isolate the variable lol

1 = x or x = 1

I believe is the answer? please comment if I'm wrong

*I WAS TOLD MY THOUGHT PROCESS IS WRONG ANYONE WHO SEES THIS PLEASE DISREGARD

5 0

3 years ago

What is equivalent to 36/54

mina [271]

Answer:

18/27 would be a equivalent fraction to 36/54

Step-by-step explanation:

36/2=18 and 54/2=27

Therefore, 18/27

5 0

3 years ago

A truck travels 52 1/2 miles and uses 2 1/2 gallons of gasoline. What is the fuel rate in miles per gallon?

kumpel [21]

Answer:

131 1/2 miles per gallon

Step-by-step explanation:

52 1/2 × 2 1/2 = 131 1/2

3 0

1 year ago

Let f(x) = tan(x) - 2/x. Let g(x) = x^2 + 8. What is f(x)*g(y)?

Tema [17]

Answer:

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Step-by-step explanation:

We are given that

$f(x)=tan(x)-\frac{2}{x}$

$g(x)=x^2+8$

We have to find $f(x)\times g(y)$

To find the value of $f(x)\times g(y)$ we will multiply f(x) by g(y)

$g(y)=y^2+8$

Now,

$f(x)\times g(y)=(tanx-\frac{2}{x})(y^2+8)$

$f(x)\times g(y)=tan(x)(y^2+8)-\frac{2}{x}(y^2+8)$

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

Hence,

$f(x)\times g(y)=y^2tan(x)+8tan(x)-\frac{2y^2}{x}-\frac{16}{x}$

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3 years ago