Answer:
m<V = 11.2 degrees
Step-by-step explanation:
In ΔUVW, the measure of ∠W=90°, UV = 6.2 feet, and WU = 1.2 feet.
From the triangle;
UV = hypotenuse = 6.2feet
WU = opposite = 1.2feet
Required
m<V
Using the SOH CAH TOA identity
sin m<V = opp/hyp
sin m<V = WU/UV
sin m<V = 1.2/6.2
sin m<V = 0.1936
m<V = arcsin(0.1936)
m<V = 11.16
m<V = 11.2 degrees ((to the nearest tenth of a degree)
Y = 30 - 2(2)
y= 30 - 4
y = 26
The measure of each base angle is 34 degrees and the measure of the vertex angle is 112 degrees
Find the diagram attached.
The base of the isosceles triangle is "b".
Since the base angles are equal, hence the sum of the interior angle is expressed as:
b + b + 112 = 180
2b + 112 = 180
2b = 180 - 112
2b = 68
b = 68/2
b = 34 degrees
Hence the measure of each base angle is 34 degrees and the measure of the vertex angle is 112 degrees
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