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Mariana [72]
3 years ago
7

In 4 ​hours, an experienced cook prepares enough pies to supply a local​ restaurant's daily order. Another cook prepares the sam

e number of pies in 7 hours. Together with a third​ cook, they prepare the pies in 2 hours. Find how long it takes the third cook to prepare the pies alone.
Mathematics
1 answer:
vodka [1.7K]3 years ago
8 0

Answer:

9\frac{1}{3}hours

Step-by-step explanation:

Let third cook take x hours to prepare the same number of  pies y alone

Let y be the number of pies

In 1 hour ,third cook prepare pies=\frac{y}{x}

One experienced cook takes time to prepare enough pies  =4 hours

In 1 hour , cook prepare pies=\frac{y}{4}

Another cook takes time to prepare same number of pies =7 hours

In 1 hour , another cook prepare pies=\frac{y}{7}

All three cooks take time to  prepare the same number of pies=2 hours

In 1 hour,all three cooks  prepare  pies=\frac{y}{2}

According to question

\frac{y}{4}+\frac{y}{7}+\frac{y}{x}=\frac{y}{2}

y(\frac{1}{4}+\frac{1}{7}+\frac{1}{x})=\frac{y}{2}

\frac{1}{4}+\frac{1}{7}+\frac{1}{x}=\frac{1}{2}

\frac{1}{x}=\frac{1}{2}-\frac{1}{4}-\frac{1}{7}

\frac{1}{x}=\frac{14-7-4}{28}=\frac{3}{28}

x=\frac{28}{3}=9\frac{1}{3} hours

Hence, the third cook takes time to prepare the same number of pies alone=9\frac{1}{3}hours

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Nonamiya [84]
H(t) = -16t² + 16 t + 480

Factor out -16
-16(t² - t - 30) 
t² - t - 30 
(t + 5)(t - 6) ⇒ t(t-6) + 5(t-6) ⇒ t² -6t + 5t - 30 ⇒ t² - t - 30

t + 5 = 0           t - 6 = 0
t = -5                t = 6

The value of t is either -5 or 6 however time can't be measured in negative form; then, it took Rose 6 seconds to hit the water.


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3 years ago
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Step-by-step explanation:

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3 years ago
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dybincka [34]

i) The given function is

f(x)=\frac{(2x+1)(x-5)}{(x-5)(x+4)^2}

The domain is

(x-5)(x+4)^2\ne 0

(x-5)\ne0,(x+4)^2\ne 0

x\ne5,x\ne -4

ii) For vertical asymptotes, we simplify the function to get;

f(x)=\frac{(2x+1)}{(x+4)^2}

The vertical asymptote occurs at

(x+4)^2=0

x=-4

iii) The roots are the x-intercepts of the reduced fraction.

Equate the numerator of the reduced fraction to zero.

2x+1=0

2x=-1

x=-\frac{1}{2}

iv) To find the y-intercept, we substitute x=0 into the reduced fraction.

f(0)=\frac{(2(0)+1)}{(0+4)^2}

f(0)=\frac{(1)}{(4)^2}

f(0)=\frac{1}{16}

v) The horizontal asymptote is given by;

lim_{x\to \infty}\frac{(2x+1)}{(x+4)^2}=0

The horizontal asymptote is y=0.

vi) The function has a hole at x-5=0.

Thus at x=5.

This is the factor common to both the numerator and the denominator.

vii) The function is a proper rational function.

Proper rational functions do not have oblique asymptotes.

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Which ordered pair is not a point of the graph of y=1/2x-7
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2w(w2 + 3w - 5) + 3w3 + 2(w2 + 1)
marysya [2.9K]

Answer:

=5w3+8w2−10w+2

Step-by-step explanation:

Simplify

1

Distribute

2

(

2

+

3

−

5

)

+

3

3

+

2

(

2

+

1

)

2

3

+

6

2

−

1

0

+

3

3

+

2

(

2

+

1

)

2

Distribute

2

3

+

6

2

−

1

0

+

3

3

+

2

(

2

+

1

)

2

3

+

6

2

−

1

0

+

3

3

+

2

2

+

2

3

Combine like terms

2

3

+

6

2

−

1

0

+

3

3

+

2

2

+

2

5

3

+

6

2

−

1

0

+

2

2

+

2

4

Combine like terms

5

3

+

6

2

−

1

0

+

2

2

+

2

5

3

+

8

2

−

1

0

+

2

sorry if it don't make sense ;c

7 0
3 years ago
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