Saul makes green paint by mixing blue paint and yellow paint.

Mathematics

2 answers:

alukav5142 [94]3 years ago

8 0

I need the picture I don’t understand what this is without he picture

oksano4ka [1.4K]3 years ago

5 0

You should include a picture so I could tell you the answer

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This morning Greg’s car had 25.25 of fuel now 1.4 gallons are left how much fuel did Greg use

tensa zangetsu [6.8K]

Answer:23.85

Step-by-step explanation:

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3 years ago

A 15 ft. telephone pole has a wire that extends from the top of the pole to the ground. The wire and the ground form a 42 angle.

erastovalidia [21]

The correct answer is A wire=22.4ft distance 16.7ft

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4 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

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3 years ago

Jeff is 6 years older than Sam. In four years he will be twice as old as Sam was 5 years ago. Find both their ages now... can u

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3 years ago

Find the condition that one root of the quadratic equation may be 1 more than the other.

Eddi Din [679]

<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>

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4 years ago