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3 years ago

What is 21000 rounded to the nearest ten thousand

Mathematics

2 answers:

Alex17521 [72]3 years ago

5 0

The answer is 20000 because you make the 1 a zero

denpristay [2]3 years ago

4 0

A number rounded to the nearest 10000, means that the last four digits of that number (on the left of the decimal point) are 0.
<span>However, if the fourth-last digit to the left of the decimal point is 5 or greater, the number to the left of that is rounded to 1 number higher. For example, if you were rounding 145293 to the nearest 10000, it would be 150000.

However, the </span>fourth-last digit to the left of the decimal point in this case is 1.
Therefore, <span> 21000 rounded to the nearest 10000 is 20000.

</span>

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How to find a slope of (-3,-3) and (5,9)

Rzqust [24]

Answer: m= 3/2

Step-by-step explanation:

Because....

if you use the slope formula y2-y1/y2-y1 .

It's going to be....

$m=\frac{9-(-3)}{5-(-3)}$

Therefor, the answer is m = $\frac{3}{2}$

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8 0

3 years ago

Simplify, write without exponents.

LuckyWell [14K]

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3 years ago

The prism shown has a volume of 35cm³. Work out the height of the triangular cross section. The length going back is 7cm and the

Gre4nikov [31]

Answer:

2.5 cm

Step-by-step explanation:

The volume of a triangular prism is cross section × length.

The cross section area is the triangle area. The triangle length is 4 cm, the height is not given. The length of the triangular prism is 7cm.

4 × h × 1/2 × 7 = 35

14h = 35

h = 35/14

h = 5/2

The height of the triangular cross section is 2.5 cm.

3 0

3 years ago

Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be

Oksana_A [137]

<h2>Hello!</h2>

The answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

To calculate the speed of the cars, we need to write two equations, one for each car, in order to create a relation between the two speeds and be able to calculate one in function of the other.

So,

Tet be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

$x_{FirstCar}=x_o+v*t$

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

$x_{SecondCar}=x_o+(v+14mph)*t$

Now, from the statement that both cars met after 2 hours and 45 minutes, and the distance between to cover (between A and B) is 264 miles, so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

$RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph$

Then, since we know that they covered a combined distance equal to 264 miles in 2 hours + 45 minutes, we have:

$2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours$

Writing the equation:

$264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph$

So, the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

$SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph$

We have that the speed of the second car is equal to 55 mph.

Hence, the answers are:

$FirstCarSpeed=41mph\\SecondCarSpeed=55mph$

Have a nice day!

7 0

3 years ago

Write the ordered pairs for the original shape and the transformation

Vadim26 [7]

For the solid line it is (0,-3), (0,3), (-3,4)
for the dotted line it is (-1,-1), (-3,-2), (-3,2)
hope this helps don't know for sure though if its right i just did the best i could do.

4 0

3 years ago