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inessss [21]
3 years ago
7

Help me plz I don't get it !!!!!!!!

Mathematics
2 answers:
HACTEHA [7]3 years ago
5 0

Answer:

B. 3

Step-by-step explanation:

The constant of proportionality is 3 because every week, the tree grows 3 more inches at a constant rate. The increase amount doesn't change. It's constantly growing by 3 inches.

I hope this helps!

Alona [7]3 years ago
3 0
Answer: B.

It grows 3 inches per week
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alexandr402 [8]

Answer:

Online Ordering is better.

Step-by-step explanation:

So you now that you save 20% if you to physical store and you save $20 if you go to the online store.

Say you are spending 100 dollars at the store to make it easy. 20% of one hundred is $20 so that is the same amount of money.

Now let’s look at the taxes and shipping so at the physical store you have to pay taxes no matter what but online you only do it if you purchase is less than $75 and we have $80 ($100–$20=$80) so at the physical store you have some amount of Mandy that is more than $80 because of taxes but if you buy online it will be exactly $80.

3 0
3 years ago
Based on the figure, select all true equations.
Svetlanka [38]

Answer:

nose pero me entiende n verdad

5 0
2 years ago
I need help understanding square roots
Vlad [161]

I wonder if you mean to write \sqrt[3]{256} in place of 3\sqrt{256}...

If you meant what you wrote, then we have

\sqrt{256}=\sqrt{16^2}=16

3\sqrt{256}=3\cdot16=48

If you meant to write \sqrt[3]{256} (the cube root of 256), then we could go on to have

\sqrt[3]{256}=\sqrt[3]{16^2}=\sqrt[3]{(4^2)^2}=\sqrt[3]{4^4}=\sqrt[3]{4^3\cdot4}=4\sqrt[3]4

6 0
3 years ago
Multiply and give the answer in scientific notation:
kakasveta [241]

Step-by-step explanation:

<em>giv</em><em>en</em><em> </em>

<em>(1.5 \times  {10}^{4} )(8 \times  {10}^{8} )</em>

<em>in</em><em> </em><em>or</em><em>der</em><em> </em><em>to</em><em> </em><em>mak</em><em>e</em><em> </em><em>multipli</em><em>cation</em><em> </em><em>easi</em><em>er</em><em> </em><em>we</em><em> </em><em>ne</em><em>ed</em><em> </em><em>to</em><em> </em><em>cha</em><em>nge</em><em> </em><em>the</em><em> </em><em>1</em><em>.</em><em>5</em><em> </em><em>into</em><em> </em><em>a</em><em> </em><em>whol</em><em>e</em><em> </em><em>number</em><em> </em><em>form</em><em>.</em>

<em>thus</em>

<em>(15 \times  {10}^{ - 1}  \times  {10}^{4} )(8 \times  {10}^{8} )</em>

<em>= (15 \times  {10}^{4 - 1} )(8 \times  {10}^{8} )</em>

<em>First</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>indic</em><em>es</em><em> </em><em>appli</em><em>ed</em><em> </em><em>there</em>

<em>=</em><em>(</em><em>1</em><em>5</em><em>×</em><em>1</em><em>0</em><em>^</em><em>3</em><em>)</em><em>(</em><em>8</em><em>×</em><em>1</em><em>0</em><em>^</em><em>8</em><em>)</em>

<em>=</em><em>(</em><em>1</em><em>5</em><em>×</em><em>8</em><em>)</em><em>(</em><em>1</em><em>0</em><em>^</em><em>3</em><em>×</em><em>1</em><em>0</em><em>^</em><em>8</em><em>)</em>

<em>=</em><em>1</em><em>2</em><em>0</em><em>×</em><em>1</em><em>0</em><em>^</em><em>3</em><em>+</em><em>8</em><em> </em><em>(</em><em> </em><em>firs</em><em>t</em><em> </em><em>law</em><em> </em><em>of</em><em> </em><em>indic</em><em>es</em><em>,</em><em> </em><em>whi</em><em>ch</em><em> </em><em>sta</em><em>tes</em><em> </em><em>that</em><em> </em><em>,</em><em> </em><em>num</em><em>bers</em><em> </em><em>o</em><em>f</em><em> the</em><em> </em><em>sa</em><em>me</em><em> </em><em>base</em><em> </em><em>multi</em><em>plying</em><em> </em><em>each</em><em> </em><em>o</em><em>ther</em><em>,</em><em> take</em><em> </em><em>on</em><em>e</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>base</em><em> </em><em>and</em><em> </em><em>add</em><em> </em><em>the</em><em> </em><em>expon</em><em>ent</em><em>.</em><em> </em><em>and</em><em> </em><em>clearly</em><em> </em><em>both</em><em> </em><em>1</em><em>5</em><em> </em><em>and</em><em> </em><em>8</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>base</em><em> </em><em>1</em><em>0</em>

<em>=</em><em>1</em><em>2</em><em>0</em><em>×</em><em>1</em><em>0</em><em>^</em><em>1</em><em>1</em>

<em>=</em><em>1</em><em>.</em><em>2</em><em>0</em><em>×</em><em>1</em><em>0</em><em>^</em><em>2</em><em> </em><em>×</em><em>1</em><em>0</em><em>^</em><em>1</em><em>1</em>

<em>=</em><em>1</em><em>.</em><em>2</em><em>0</em><em>×</em><em>1</em><em>0</em><em>^</em><em>1</em><em>1</em><em>+</em><em>2</em>

<em>=</em><em>1</em><em>.</em><em>2</em><em>0</em><em>×</em><em>1</em><em>0</em><em>^</em><em>1</em><em>3</em>

<em>so</em><em> </em><em>the</em><em> </em><em>a</em><em>nswer</em><em> </em><em>is</em><em> </em><em>alt</em><em> </em><em>B</em>

7 0
3 years ago
Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (
valentinak56 [21]

Answer:

23

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4)  and (5, 1, 0)

A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)

= 1(-4) - 1(3) + 5(6)

= -4 - 3 + 30

= 23

So the volume of the parallelepiped is 23

4 0
2 years ago
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