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olganol [36]
3 years ago
15

Find the value of x.

Mathematics
1 answer:
-Dominant- [34]3 years ago
3 0

Answer:

x = -7

Step-by-step explanation:

All triangle angles add up to 180

84 + x + 59 + x + 51 = 180

2x + 194 = 180

2x = 180 - 194

2x = -14

x = -7

You might be interested in
Subtract 2x^2-3xy+4y^2 from 3x^2-5xy-6y^2
Diano4ka-milaya [45]

Answer:

-x^{2} +2xy+10y^{2}

Step-by-step explanation:

2x^2-3xy+4y^2-(3x^2-5xy-6y^2)\\2x^2-3xy+4y^2-3x^2+5xy+6y^2\\-x^{2} +2xy+10y^{2}

8 0
3 years ago
a line with a slope of 1 passes through the point (5,10). what is the equation in this slope-intercept form?
patriot [66]

Answer:

y=x+5

Step-by-step explanation:

So first you need to plug everything into the point-slope formula which is

y-y1=m(x-x1)

m being the slope and y1 and x1 being the point (5,10)

So once you plug it in it should look like this: y-10=1(x-5)

Now you solve it

First you need to distribute 1 in 1(x-5) which is (x-5)

Now you have y-10=x-5

Then you add 10 to both sides which is y=x+5

Your answer is y=x+5

8 0
3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
5. Michael is going to buy a new pair of shoes. The shoes cost $44.20. He has to pay 15% tax on the
solniwko [45]

Answer:

$50.83

Step-by-step explanation:

44.20 x .15 = 6.63

44.20 + 6.63= 50.83

8 0
3 years ago
Read 2 more answers
Solve it:3/10×7/10=21/100
egoroff_w [7]
I'm gonna guess you're asking if the equation is true or false.
Well, the equation is True. 3/10 * 7/10 is 21/100, or in decimal form 0.21.
Converting 21/100 to a decimal is 0.21.
0.21 = 0.21.
21/100 = 21/100.
7 0
3 years ago
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