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3 years ago

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Price-club sells a 12-ounce box of crackers for $2.59 and Shop Mart sells 1-pound box of crackers for $4.68. The unit price at P

rice-Club is $ per ounce, and the unit price at Shop Mart is $per ounce.

1 answer:

Vesna [10]3 years ago

8 0

Answer:

The unit price at Price-Club is $0.2158 per ounce.

The unit price at Shop Mart is $0.2925 per ounce.

Step-by-step explanation:

Price Club:

12-ounce box of crackers for $2.59

So

12 ounces - $2.59

1 ounce - x

$12x = 2.59$

$x = \frac{2.59}{12}$

$x = 0.2158$

The unit price at Price-Club is $0.2158 per ounce.

Shop Mart:

1-pound box of crackers for $4.68.

1 pound is 16 ounces. So

16 ounces - $4.68

1 ounce - x

$16x = 4.68$

$x = \frac{4.68}{16}$

$x = 0.2925$

The unit price at Shop Mart is $0.2925 per ounce.

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<em>x 1/8 1/4 1/2 1 2</em>

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<em></em>

Step-by-step explanation:

<u><em>Explanation</em></u> :-

Given logarithmic function $y = log_{b} (x)$ if b >1

Given first table

i)

put x = $\frac{1}{8}$ given b > 1 so we can choose b = 2

$y = log_{2} (\frac{1}{8} )$

$y = log_{2} (2^{-3} )$

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-3} ) = -3 log_{2} (2) = -3 (1) = -3$

<em>y = -3</em>

<em>ii)</em>

<em>put x = </em> $\frac{1}{4}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{4} )$ <em></em>

<em></em> $y = log_{2} (2^{-2} )$ <em></em>

we will apply logarithmic formula

log x ⁿ = n log (x)

$y = log_{2} (2^{-2} ) = -2 log_{2} (2) = -2 (1) = -2$

<em>y = -2</em>

<em>iii) </em>

<em>put x = </em> $\frac{1}{2}$ <em> given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (\frac{1}{2} )$ <em></em>

$y = log_{2} (2^{-1} )$

<em>we will apply logarithmic formula </em>

<em>log x ⁿ = n log (x)</em>

$y = log_{2} (2^{-1} ) = -1 log_{2} (2) = - (1) = -1$

<em>y = -1</em>

<em>iv) </em>

<em>put x = 1 given b > 1 so we can choose b = 2</em>

<em></em> $y = log_{2} (1 )$ <em> = 0</em>

<em>y = 0</em>

<em>v) </em>

<em>put x = </em> $2$ <em> given b > 1 so we can choose b = 2</em>

$y = log_{2} (2 )$

<em>y = 1</em>

<em></em>

<u><em>Final answer:-</em></u>

<u><em>The satisfied table of the given function</em></u>

<em>x 1/8 1/4 1/2 1 2</em>

<em>y -3 -2 -1 0 1</em>

<em></em>

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3 years ago

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