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shusha [124]
4 years ago
11

A cable 20 feet long connects the top of a flagpole to a point on the ground that is 16 feet from the base of the pole. How tall

is the flagpole?(A) 8 ft.(B) 10 ft.(C) 16 ft. (D) 26 ft.

Mathematics
1 answer:
dusya [7]4 years ago
3 0
<h2>Answer:</h2>

The height of the flagpole is: 12 ft.

<h2>Step-by-step explanation:</h2>

Let the height of the flagpole be: x ft.

Now, we can model this problem with the help of a right angled triangle such that the hypotenuse of the triangle is: 20 feet

and one of the leg of the right triangle is: 16 feet

Now, in order to find the other leg i.e. x we need to use the Pythagorean Theorem.

i.e.

20^2=x^2+16^2\\\\i.e.\\\\400=x^2+256\\\\x^2=400-256\\\\x^2=144\\\\x=\pm 12

But the height can't be negative.

Hence, we get:

x=12

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shusha [124]

Answer:

Step-by-step explanation:

These triangles are similar triangles, so there is a number that you can multiply the sides of TUV to find the side lengths of QRS. looking at the triangle, the similar sides are RS being similar to UV and RQ being similar to UT.

If RS~UV, then there is a ratio between them. 54/36=1.5. The ratio is 1.5.

RQ~UT, and by a factor of 1.5, so divide RQ by the scale factor. 24/1.5=16. UT=16=x+5.

x+5=16, subtract 5 from both sides.

x=11

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