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saul85 [17]
3 years ago
5

Find the exact value of each expression . Do not use a calculator .

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0
The attached table is one that it is convenient for you to memorize as long as you're taking courses involving angles. For the inverse functions, find the column corresponding to the function, then look for the value in that column. The angle at the beginning of that row is the answer to your question.

8. \cos^{-1}(0)= 90^{\circ}=\dfrac{\pi}{2}

9. \sin^{-1}(1)= 90^{\circ}=\dfrac{\pi}{2}

10. \tan^{-1}\left( \dfrac{\sqrt{3}}{3} \right)=30^{\circ}=\dfrac{\pi}{6}

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Whar does7^or other numbers like it mean?
likoan [24]
7^0=1

7^1=7

7^2=7*7=49

7^3=7*7*7=343

etc... etc...
4 0
3 years ago
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Lmno is a kite find the length of ln
Llana [10]
Where are the numbers so that people can help you
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3 years ago
Find the value of x. Give reasons to justify your solution. C ∈ AE
saw5 [17]

Answer:

x = 11º

Step-by-step explanation:

1. Notice Parallel Lines

2. Understand Angle Relationships When Parallel Lines Are Present (e.g., alternate interior/exterior)

3. ∠CAB ≅ ∠DCA ∴ m∠CAB = 33º

4. Use exterior angle theorem: the sum of non-adjacent angles of the same triangle which the exterior angle is drawn is equal to the measure of that angle.

5. Therefore write and solve the equation 2x + 33º (sum of non-adjacent interior angles) = 5x (exterior angle).

  • 2x + 33 = 5x (C.L.T or <u>C</u>ombine <u>L</u>ike <u>T</u>erms)
  • 3x = 33 (inverse operations; divide by 3)
  • x = 11º (remember to apply units)
7 0
3 years ago
Every recurring decimal is​
prisoha [69]

Answer:

Every repeating or terminating decimal is a rational number

Each repeating decimal number satisfies a linear equation with integer coefficients, and its unique solution is a rational number.

6 0
3 years ago
What is the solution to the equation? (-9x+5)^1/2=(3+4x)1/2
Phoenix [80]
<span>x in (-oo:+oo)

((5-9*x)^1)/2 = ((4*x+3)^1)/2 // - ((4*x+3)^1)/2

((5-9*x)^1)/2-(((4*x+3)^1)/2) = 0

(5-9*x)/2-((4*x+3)/2) = 0

(5-9*x)/2+(-1*(4*x+3))/2 = 0

5-1*(4*x+3)-9*x = 0

2-13*x = 0

(2-13*x)/2 = 0

(2-13*x)/2 = 0 // * 2

2-13*x = 0

2-13*x = 0 // - 2

-13*x = -2 // : -13

x = -2/(-13)

x = 2/13

x = 2/13</span>
4 0
4 years ago
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