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3 years ago

Find the exact value of each expression . Do not use a calculator .

Mathematics

1 answer:

Alex73 [517]3 years ago

8 0

The attached table is one that it is convenient for you to memorize as long as you're taking courses involving angles. For the inverse functions, find the column corresponding to the function, then look for the value in that column. The angle at the beginning of that row is the answer to your question.

8. $\cos^{-1}(0)= 90^{\circ}=\dfrac{\pi}{2}$

9. $\sin^{-1}(1)= 90^{\circ}=\dfrac{\pi}{2}$

10. $\tan^{-1}\left( \dfrac{\sqrt{3}}{3} \right)=30^{\circ}=\dfrac{\pi}{6}$

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Jaffrey was offered a job at $950 per month with a $22 increase every month for the first year. How much money can he make in th

iogann1982 [59]

Answer:

Jaffrey will end up making $1214 in the first year

Step-by-step explanation:

950 + 12(22) = ?

first lets find out what 12 * 22 =?

12 * 22 = 264

now lets add 264 to 950

264 + 950 = 1214

5 0

3 years ago

Henry wants to get a job this summer. He can either mow lawns or work in the local library. What is the opportunity cost if he d

Karolina [17]

B. The chance to earn by working in a library.

7 0

3 years ago

Read 2 more answers

Kurt johnson delivers packages for a delivery company. he receives $7.50 for every package delivered. what does kurt earn in a w

Ivan

Y = 7.50x.....y = earnings per week , x = number of packages delivered

48 packages.....so x = 48
y = 7.50(48)
y = 360.....so if he delivers 48 packages, he earns $ 360

8 0

3 years ago

Read 2 more answers

Solve the following recurrence relation: <br> <img src="https://tex.z-dn.net/?f=A_%7Bn%7D%3Da_%7Bn-1%7D%2Bn%3B%20a_%7B1%7D%20%3D

-Dominant- [34]

By iteratively substituting, we have

$a_n = a_{n-1} + n$

$a_{n-1} = a_{n-2} + (n - 1) \implies a_n = a_{n-2} + n + (n - 1)$

$a_{n-2} = a_{n-3} + (n - 2) \implies a_n = a_{n-3} + n + (n - 1) + (n - 2)$

and the pattern continues down to the first term $a_1=0$ ,

$a_n = a_{n - (n - 1)} + n + (n - 1) + (n - 2) + \cdots + (n - (n - 2))$

$\implies a_n = a_1 + \displaystyle \sum_{k=0}^{n-2} (n - k)$

$\implies a_n = \displaystyle n \sum_{k=0}^{n-2} 1 - \sum_{k=0}^{n-2} k$

Recall the formulas

$\displaystyle \sum_{n=1}^N 1 = N$

$\displaystyle \sum_{n=1}^N n = \frac{N(N+1)}2$

It follows that

$a_n = n (n - 2) - \dfrac{(n-2)(n-1)}2$

$\implies a_n = \dfrac12 n^2 + \dfrac12 n - 1$

$\implies \boxed{a_n = \dfrac{(n+2)(n-1)}2}$

4 0

2 years ago

9/10-1/3-1/5 find the fraction

Zanzabum

Find a common multiple in between the denominators.
10 and 3 and 5 -> the least common multiple is 30.

Change all the denominators to 30 by multiplying the top and bottom by the same number.

9/10=27/30
1/3=10/30
1/5=6/30

Subtract!
27/39-10/30-6/30=11/30

The answer is 11/30

Hope this helps!

3 0

3 years ago