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saul85 [17]
3 years ago
5

Find the exact value of each expression . Do not use a calculator .

Mathematics
1 answer:
Alex73 [517]3 years ago
8 0
The attached table is one that it is convenient for you to memorize as long as you're taking courses involving angles. For the inverse functions, find the column corresponding to the function, then look for the value in that column. The angle at the beginning of that row is the answer to your question.

8. \cos^{-1}(0)= 90^{\circ}=\dfrac{\pi}{2}

9. \sin^{-1}(1)= 90^{\circ}=\dfrac{\pi}{2}

10. \tan^{-1}\left( \dfrac{\sqrt{3}}{3} \right)=30^{\circ}=\dfrac{\pi}{6}

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Answer only if you know<br><br> HELP PART A AND PART B
VARVARA [1.3K]

Answers:

  • Part A) There is one pair of parallel sides
  • Part B) (-3, -5/2) and (-1/2, 5/2)

====================================================

Explanation:

Part A

By definition, a trapezoid has exactly one pair of parallel sides. The other opposite sides aren't parallel. In this case, we'd need to prove that PQ is parallel to RS by seeing if the slopes are the same or not. Parallel lines have equal slopes.

------------------------

Part B

The midsegment has both endpoints as the midpoints of the non-parallel sides.

The midpoint of segment PS is found by adding the corresponding coordinates and dividing by 2.

x coord = (x1+x2)/2 = (-4+(-2))/2 = -6/2 = -3

y coord = (y1+y2)/2 = (-1+(-4))/2 = -5/2

The midpoint of segment PS is (-3, -5/2)

Repeat those steps to find the midpoint of QR

x coord = (x1+x2)/2 = (-2+1)/2 = -1/2

y coord = (x1+x2)/2 = (3+2)/2 = 5/2

The midpoint of QR is (-1/2, 5/2)

Join these midpoints up to form the midsegment. The midsegment is parallel to PQ and RS.

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