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Ghella [55]
3 years ago
7

A very small round ball is located near a large solid sphere of uniform density. The force that the large sphere exerts on the b

all A very small round ball is located near a large solid sphere of uniform density. The force that the large sphere exerts on the ball a. is independent of the mass of the sphere. b. can only be calculated using calculus. c. is approximately the same as it would be if all the mass of the sphere were concentrated at the center of the sphere. d. is independent of the mass of the ball. e. is exactly the same as it would be if all the mass of the sphere were concentrated at the center of the sphere.
Physics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

Option e

Explanation:

The Law of Universal Gravitation states that every point mass attracts every other point mass in the universe by a force pointing in a straight line between the centers-of-mass of both points, and this force is proportional to the masses of the objects and inversely proportional to their separation This attractive force always points inward, from one point to the other. The Law applies to all objects with masses, big or small. Two big objects can be considered as point-like masses, if the distance between them is very large compared to their sizes or if they are spherically symmetric. For these cases the mass of each object can be represented as a point mass located at its center-of-mass.

The same force is applied to both the balls.

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Answer:

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Explanation:

Por la definición de trabajo sabemos que el montañero debió contrarrestar trabajo causado por la gravedad terrestre. Si asumimos que el cambio de la altura es muy pequeño en comparación con el radio del planeta (6371 kilómetros vs. 0,5 kilómetros), entonces podemos considerar que la aceleración gravitacional es constante y la ecuación de trabajo (\Delta W), medido en joules, que reducida a:

\Delta W = m\cdot g\cdot \Delta z (1)

Donde:

m - Masa del montañero, medido en kilogramos.

g - Aceleración gravitacional, medida en metros por segundo al cuadrado.

\Delta z - Distancia vertical de ascenso del montañero, medida en metros.

Si tenemos que m = 65\,kg, g = 9,807\,\frac{m}{s^{2}} y \Delta z = 500\,m, entonces el trabajo realizado por el montañero para subir es:

\Delta W = (65\,kg)\cdot \left(9,807\,\frac{m}{s^{2}} \right)\cdot (500\,m)

\Delta W = 318727,5\,J

El trabajo realizado para subir los últimos 500 metros es 318727,5 joules.

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