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Leni [432]
3 years ago
13

Can anyone help me with this question?

Physics
1 answer:
yan [13]3 years ago
7 0

Answer: The spring potential energy must equal or exceed the energy to raise the mass to loop height and the minimum kinetic energy needed to keep the mass in contact with the top of the loop

kd² = 5Mrg

h = kd²/2Mg

Explanation:

at top of loop

Mv²/r = Mg

v² = rg

½kd² = ½Mv² + Mgh'

½kd² = ½M(rg) + Mg(2r)

½kd² = 2.5Mrg

kd² = 5Mrg

½kd² = Mgh

h = kd²/2Mg

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