All categories

3 years ago

Simplify the following expression 7d-9-6d-4

Mathematics

2 answers:

vodomira [7]3 years ago

6 0

Answer:

d-13

Step-by-step explanation:

We can simplify variables then numbers:

7d - 9 - 6d - 4.

7d - 6d - 9 - 4

d - 9 - 4

d - 13

kotykmax [81]3 years ago

3 0

See picture for answer.

You might be interested in

A circle has a central angle EOG that measures 60° and a radius 15 feet what is the length of the intercepted arc E.G.

sashaice [31]

Arc length = radius * central angle (radians)
60 degrees = PI/3 radians
arc length = 15 * PI/3
arc length = 5 * PI

6 0

3 years ago

Taylor is buying a chest freezer that had an original price of $145 but is

mixas84 [53]

Answer:B

Step-by-step explanation:

It's 116.09

6 0

3 years ago

What is 3/5 of 24? What is the formula

Anon25 [30]

I got 18 I am not sure if it is right

8 0

3 years ago

Read 2 more answers

What is the standard form of the equation of the line through (6,-3) with a slope of 2/3

tangare [24]

Ax+by=c is the standard form
you are given the slope and a point, so first write the equation in point-slope form:
y-(-3)=2/3(x-6)
expand the equation: y+3=(2/3)x-4
(2/3)x-y=7 is the standard form

5 0

3 years ago

Read 2 more answers

The University of Washington claims that it graduates 85% of its basketball players. An NCAA investigation about the graduation

Nonamiya [84]

Probabilities are used to determine the chances of events

The given parameters are:

Sample size: n = 20
Proportion: p = 85%

<h3>(a) What is the probability that 11 out of the 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 11) = ^{20}C_{11} \times (85\%)^{11} \times (1 - 85\%)^{20 -11}$

This gives

$P(x = 11) = 167960 \times (0.85)^{11} \times 0.15^{9}$

$P(x = 11) = 0.0011$

Express as percentage

$P(x = 11) = 0.11\%$

Hence, the probability that 11 out of the 20 would graduate is 0.11%

<h3>(b) To what extent do you think the university’s claim is true?</h3>

The probability 0.11% is less than 50%.

Hence, the extent that the university’s claim is true is very low

<h3>(c) What is the probability that all 20 would graduate? </h3>

Using the binomial probability formula, we have:

$P(X = x) = ^nC_x p^x(1 - p)^{n -x}$

So, the equation becomes

$P(x = 20) = ^{20}C_{20} \times (85\%)^{20} \times (1 - 85\%)^{20 -20}$

This gives

$P(x = 20) = 1 \times (0.85)^{20} \times (0.15\%)^0$

$P(x = 20) = 0.0388$

Express as percentage

$P(x = 20) = 3.88\%$

Hence, the probability that all 20 would graduate is 3.88%

<h3>(d) The mean and the standard deviation</h3>

The mean is calculated as:

$\mu = np$

So, we have:

$\mu = 20 \times 85\%$

$\mu = 17$

The standard deviation is calculated as:

$\sigma = np(1 - p)$

So, we have:

$\sigma = 20 \times 85\% \times (1 - 85\%)$

$\sigma = 20 \times 0.85 \times 0.15$

$\sigma = 2.55$

Hence, the mean and the standard deviation are 17 and 2.55, respectively.