Since you need an isolated variable to use the substitution method, we need to re-arrange one of the equations. This will probably be easiest to do with the first one.
Add 5y to both sides of the first equation.
x=10+5y
Now, in the second equation, put in 10+5y in any spot that has an x.
2(10+5y)-10y=20
Distribute the 2 to both numbers in the parenthesis.
20+10y-10y=20
Combine like terms.
20=20
This means that the two equations are actually the same. You can see this if you multiply the whole first equation by 2
2(x-5y=10)
2x-10y=20, which is the same as the second equation. Therefore, the two equations are actually the same one.
FYI - 14,15,16 are correct.
17. a) 7 (nearest integer), b) 6.8 (nearest tenth)
18. a) 14 (nearest integer), b) 13.8 (nearest tenth)
19. 
--> simplified to = 2
<em>-- let me know if you have any questions regarding this. </em>
I think that would be a rectangle with sides 13 and 8 Which = 104 ins^2
Answer:
Step-by-step explanation:
Given the expression;
g(t) = 6 + t + t²/√t
This can be rewritten as;
g(t) = 6 + t +t²/t^1/2
g(t) = 6 + t +t^{2-1/2}
g(t) = 6 + t +t^3/2
Integrate the result
Using the formula x^{n+1}/n+1
Answer:
8 and 4
Step-by-step explanation:
You find half of the sum and subtract half of the differece for 6 and the other 6 you add the hal of the difference.
