Answer:
V=15.44
Step-by-step explanation:
We have a formula
V=\int^{π/3}_{-π/3} A(x) dx ,
where A(x) calculate as cross sectional.
We have:
Inner radius: 5 + sec(x) - 5= sec(x)
Outer radius: 7 - 5=2, we get
A(x)=π 2²- π· sec²(x)
A(x)=π(4-sec²(x))
Therefore, we calculate the volume V, and we get
V=\int^{π/3}_{-π/3} A(x) dx
V=\int^{π/3}_{-π/3} π(4-sec²(x)) dx
V=[ π(4x-tan(x)]^{π/3}_{-π/3}
V=π·(8π/3-2√3)
V=15.44
We use a site geogebra.org to plot the graph.
<h3>
Answer: Choice H) 2</h3>
=============================================
Explanation:
Recall that the pythagorean trig identity is 
If we were to isolate sine, then,
We don't have to worry about the plus minus because sine is positive when 0 < x < pi/2.
Through similar calculations, 
Cosine is also positive in this quadrant.
-------------
So,
Therefore,
is an identity as long as 0 < x < pi/2
Answer:
39 Would be your best guess since the literal percent is 38.95 or 38 19/30
Step-by-step explanation:
The answer you are looking for is "conditional".
