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Ad libitum [116K]
3 years ago
7

Choose all items that represent characteristics of the anchor tag.

Computers and Technology
1 answer:
laila [671]3 years ago
6 0

Answer:

put full question or book or article

Explanation:

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Question 1 Which portion of the PuTTY package allows you to perform file transfers using the SCP (Secure Copy) protocol?
Artyom0805 [142]

There are different aspect of computing. The portion of the PuTTY package that allows you to perform file transfers using the SCP (Secure Copy) protocol is pscp.exe.

The pscp.exe tool commonly called the PuTTY Secure Copy Client is known to be the only portion of the Putty package that can let you copy files to and from remote computers through the use of the SCP.

Secure Copy (SCP)  is simply defined as a computer command that one can use in Linux to copy files from one computer to another on a network.  PuTTY is simply known to be a free implementation of SSH (and telnet) used for computer that running Microsoft Windows.

Learn more about the PuTTY package from

brainly.com/question/13171394

8 0
3 years ago
Roses are red, violets are blue, I'm going to ki.ll myself, to make life better for you.
Shtirlitz [24]

Answer:

i like this poem helps out the world

Explanation:

p,s. deserves brainiest

6 0
3 years ago
Read 2 more answers
After your yearly checkup, the doctor has bad news and good news. The bad news is that you tested positive for a serious disease
umka2103 [35]

Answer:

The probability that you have the disease, given that your test is positive is ≈ 0.0098

Explanation:

This is a conditional probability problem.

Let P(A|B) denote the conditional probability of A given B and it satisfies the equation

  • (1) P(A|B) = P(A) × P(B|A) / P(B)

We have the the probabilities:

  • P(Testing Positive | Having Disease) =0.99
  • P(Testing Negative | Not Having Disease) =0.99
  • P(Testing Positive | Not Having Disease) = 1-0.99=0.01
  • P(Having Disease) = 0.0001 (striking only one in 10,000 people)
  • P(Not Having Disease)= 1 - 0.0001 = 0.9999

<u>We can calculate</u>:

P(Testing Positive) =

P(Having Disease) × P(Testing Positive | Having Disease) + P(Not Having Disease) × P(Testing positive | Not Having Disease )  = 0.0001×0.99 + 0.9999×0.01 =0.010098

<u>from </u><u>(1) </u><u>we have the equation</u>:

P(Having Disease|Testing Positive)=P(Having Disease) × P(Testing Positive | Having Disease)/ P(Testing Positive) = 0.0001×0.99/0.010098≈0.0098

Thus, the probability that you have the disease, given that your test is positive is ≈ 0.0098

3 0
4 years ago
How do you change a automatic transmission
irinina [24]

Answer:

ohhh ok to all transactions.

6 0
3 years ago
Dim Inventory() as Integer = {357, 126, 220}Call Stock(Inventory(2),Me.lblOutput)Sub Stock (ByVal Number As Integer, ByRef lblLa
aalyn [17]

Answer:

The answer is "Option c".

Explanation:

In the given visual basic code, an integer array "Inventory" is declared, that includes 3 elements, that are "357, 126, and 220". In the next line, a call stock function is used, in the function, the array is passed as a parameter and in array parameter, the index value that is "2" is passed. This function use label to print array index value, that is "220". and other options are incorrect that can be described as follows:

  • Option a and Option b both are wrong because array indexing always starts with 0 and ends with n-1, and in this array, it will take index value 2, which is not equal to 357 and 126.

6 0
3 years ago
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