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ExtremeBDS [4]
3 years ago
13

What is the product of -2x^3+x-5 and x^3-3x-4 ?

Mathematics
1 answer:
murzikaleks [220]3 years ago
6 0
To find the product of <span>-2x^3+x-5 and x^3-3x-4, we need to multiply each term in the first polynomial by the second polynomial. (So, x^3 - 3x - 4) times ....
-2x^3 = -2x^6 + 6x^4 + 8x^3
x = x^4 - 3x^2 - 4x
-5 = -5x^3 + 15x + 20
If we add all these together, we get (-2x^6 + 7x^4 + 3x^3 - 3x^2 + 11x + 20)</span>
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ANSWER THREE THROUGH FIVE , ILL GIVE YOU BRAINLIST!!!
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Answer:

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3) diameter of penny = 19 mm

                          r = 19/2 = 9.5 mm

Area of penny = πr²

                        = 3.14 * 9.5 * 9.5

                         = 283.385

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                          r = 21/2 = 10.5 mm

Area of nickel  = πr²

                         = 3.14 * 10.5 *10.5

                        = 346.185

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346.19 - 283.39 = 62.8 mm²

Area of Canadian nickel is greater than Canadian penny by 32.6 mm²

4)  r = 12 mm

Area of circle = πr²

                      = 3.14 * 12 * 12

                       =  452.16 mm²

5) r  = 20 cm

Area of circle =  πr²

                      = 3.14 * 20 * 20

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