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3 years ago

How do i graph q is greater than -1.3 on a number line

Mathematics

1 answer:

kompoz [17]3 years ago

5 0

Answer:

an open circle on -1.3 on the line and draw a line to the right with an arrow.

Step-by-step explanation:

On your number line, draw an open circle on -1.3 and then draw a line on the number line going to the right and ending with an arrow at the end. The open circle means that it is that starting point, but is not equal to it.

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PLEASE HELP I HAVE AN F IN MATH I HAVE NO IDEA HOW TO DO THIS!!

Galina-37 [17]

Answer:

1. C=10.6

2. C=11.2

4. C=23.4

5. C=38.4

Step-by-step explanation:

You can find the answer to these by doing the Pythagorean theorem.

a^2 + b^2 = c^2

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2 years ago

Answer true or false.

garik1379 [7]

Answer:

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3 years ago

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Every winter I fly home to Michigan it takes five hours what is my average speed

nignag [31]

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2 years ago

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Please help me I’m struggling :’(

Vesna [10]

Answer:

B. $x = \sqrt{40}$

Step-by-step explanation:

Using Pythagorean theorem, find the value of x.

Pythagorean theorem is given as $c^2 = a^2 + b^2$

Where,

c is the longest side of a right angled ∆ = the hypotenuse = x

a and b are legs of the right angled ∆ = 2 and 6

Plug in the values into the equation and solve for x

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5 0

3 years ago

Vector u has a magnitude of 5sq rt 3 feet and is directed due west. Vector v has a magnitude

Vikki [24]

The magnitude and the direction angle for the resultant vector are 10N and 120degrees respectively

The formula for calculating the resultant vector is expressed as:

$R^2 = u^2 + v^2\\R =\sqrt{u^2+v^2}$

Given the following distances:

u = -5√3 feet (west direction)

v = 5 feet

Substitute the given values into the formula above;

$R=\sqrt{(5\sqrt{3} )^2+5^2} \\R=\sqrt{(25 \times 3)+25}\\R=\sqrt{75 + 25}\\R=\sqrt{100}\\R = 10 feet$

The magnitude of the resultant vector is 10feet

Get the direction:

$\theta = tan^{-1}\frac{y}{x} \\\theta = tan^{-1}\frac{5}{-5\sqrt{3} }\\\theta =tan^{-1}\frac{-1}{\sqrt{3} }\\\theta = -60^0$

Since tan is negative in the second quadrant, hence;

$\theta = 180 - 60\\\theta = 120^0$

Hence the magnitude and the direction angle for the resultant vector are 10N and 120degrees respectively.

Learn more here: brainly.com/question/5177683

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2 years ago