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Licemer1 [7]
3 years ago
14

When constructing inscribed polygons and parallel lines, how are the steps similar?A. A protractor and ruler are used to take ac

curate measurements.B. A compass is used to draw arcs.C. Four right angles are created.D.There are no similarities.
Mathematics
1 answer:
Lorico [155]3 years ago
6 1

Answer:

C. Four right angles are created

Step-by-step explanation:

This is because right angles are formed usually by polygons so in this case it wouldn't be any different.

- At the cause of it being polygons, it also helps it to be parallel lines, which it is.

Leading it to be further more right angles.

Now how do we get four right angles?

We get four right angles by seeing the right inscribed "measurements", by at least seeing it in the "usual" contact.

I hope this helps, If I did something wrong please tell me!

Have a good day!

jorelis
2 years ago
wrong!
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What is 0.5 repeating as a fraction in simplest form
Solnce55 [7]

Answer:

5/9

Step-by-step explanation:

Start be letting x = 0.555...

Our original equation is:

x = 0.555...

There is only one digit repeating, the 5, so we multiply both sides of that equation by 10 and write it above the original equation.

10x = 5.555...

   x = 0.555...

Now we subtract the second equation from the first equation as written above.

9x = 5

Divide both sides by 9.

x = 5/9

0.555... = 5/9

6 0
3 years ago
If y varies directly as x, find the constant of variation if y = 12 when x = 1/3
Mashutka [201]
The constant is 36
because direct variation y/x
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3 years ago
Real World Scenario:
iragen [17]

The distance of a train from the city depends on the speed, the time of

travel, and direction of motion of the train.

Correct responses:

  • Distance Train A is from the city: <u>750 - 75·t</u>
  • Distance Train B is from the city: 50·t
  • After <u>six</u> hours, the two trains are the same distance from the city
  • At that time both trains will be <u>300</u> miles away

1) From the time of departure of Train B to just before 6 hours after Train B's departure; 0 ≤ t < 6 hours

2) At time period, t > 6 hours

3) 250 miles

<h3>Method used to find the above response</h3>

Given:

The distance of train A from the city = 750 miles

Speed of train A = 75 mph

Time at which Train B leaves the city = When Train A is 750 miles from the city

Speed of Train B = 50 mph

Solution:

The equations are;

  • Distance of Train A from the city is; <u>x₁ = 750 - 75·t</u>
  • Distance of Train B from the city is <u>x₂ = 50·t</u>

When the train are the same distance from the city, we have;

750 - 75·t = 50·t

750 = 50·t + 75·t = 125·t

Therefore;

  • t = \mathbf{\dfrac{750}{125}} = 6

The time it takes the two trains to be the same distance from the city is 6 hours.

Which gives;

  • After <u>6</u> hours, the two trains are the same distance from the city.

The distance the trains will be after 6 hours is therefore;

750 - 75 × 6 = 300

The distance of the trains from the city after 6 hours = 300 miles

Therefore, we have;

  • At that time both trains will be <u>300</u> miles away

1) The time period Train A is further from the city is before the first 6 hours elapse; <u>0 hours ≤ t < 6 hours</u>

2) The Train B is further from the city after 6 hours of its departure from the city; <u>t > 6 hours</u>

3) The distance of Train A from the city after 4 hours is given as follows;

x₁ = 750 - 75 × 4 = 450

x₁ = 450 miles

The distance of Train B from the city after 4 hours is; x₂ = 50 × 4 = 200

x₂ = 200 miles

Therefore;

  • The distance between the trains after 4 hours = 450 miles - 200 miles = <u>250 miles</u>

Learn more about distance and time relationship equation here:

brainly.com/question/10804931

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X^lg(x)=100^x find x
Wittaler [7]

x^lg(x)=100^x<span>
</span>


X^lg(x)=100^x:x  |Solve \ for \ x|


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<span>
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<span>lg (x ^ lg (x)) = lg (100x)&#10;&#10;</span>

<span>
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<span>lg ^ 2 (x) = 2 + lgx</span>

<span>
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lg 2 ^ x-lg x -2 = 0


lg x = 2 x = 100


lg x = -1 x = \dfrac{1}{10} = 0.1

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Answer:

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Step-by-step explanation:

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