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Law Incorporation [45]
3 years ago
12

Given:f(x)=x^2-3 and g(x)=x+1 The composite function g*f is

Mathematics
1 answer:
kupik [55]3 years ago
4 0
C will be the answer to the equation
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Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Supersc
MAVERICK [17]

Answer:

\displaystyle \frac{5x}{8y^{4}}\sqrt{x}

Step-by-step explanation:

<u>Simplfy in Algebra </u>

We have the following expression

\displaystyle E=\sqrt{\frac{25x^9y^3}{64x^6y^{11}}}

Simplifying like factors in the denominator and numerator

\displaystyle E=\sqrt{\frac{25x^3}{64y^{8}}}

All the factors are perfect squares except x^3, thus we rewrite:

\displaystyle E=\sqrt{\frac{25xx^2}{64y^{8}}}

Taking the square root of all the perfect square factors:

\boxed{\displaystyle E=\frac{5x}{8y^{4}}\sqrt{x}}

5 0
4 years ago
Read 2 more answers
1. Use Excel to answer the following. In each question, find the blank to make the statement true. Note that Z represents we are
Sati [7]

Answer:

1. A: 0.25; B: 0.03; C: 1.41; D: -0.28

2. A: 0.39; B: 0.06; C: 40.30; D: 21.81

Step-by-step explanation:

For CDF lookups, we used the Excel NORMDIST(x, mean, stdev, TRUE) function. For inverse CDF lookups, we used the NORMINV(x, mean, stdev) function.

Each of these functions works with the area under the curve from -∞ to x, so for cases where we're interested in the upper tail, we subtract the probability from 1, or subtract the x value from twice the mean.

For question 1, we computed the Z values in each case. The NORMDIST function works directly with x, mean, and standard deviation, so does not need the z value.

6 0
4 years ago
After you find the solution, how would you check to make sure your answer is correct?
krek1111 [17]

Answer:

Plug in your variables value.

Step-by-step explanation:

For your case, plug in -6 into the y slot

12(5+2y)= -(6-9y) +4y

12(5+2x-6)= -(6-9x-6)+4y see if that works!

5 0
3 years ago
Read 2 more answers
I WILL MAKE YOU BRANILEST!! PLEASE HELO FAST!!
astra-53 [7]

Answer:

20 Quarters = $5, add 10 dimes to make it $6 and 10 x 2 = 20 so your answer is 10 dimes

Step-by-step explanation:

6 0
3 years ago
Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1
mafiozo [28]

Answer:

(a).   y'(1)=0  and    y'(2) = 3

(b).  $y'(t)=kb2t\cos(bt^2)$

(c).  $ b = \frac{\pi}{2} \text{ and}\  k = \frac{3}{2\pi}$

Step-by-step explanation:

(a). Let the curve is,

$y(t)=k \sin (bt^2)$

So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value x_{0}  which lies in the domain of f where the derivative is 0.

Therefore,  y'(1)=0

Also given that the derivative of the function y(t) is 3 at t = 2.

Therefore, y'(2) = 3.

(b).

Given function,    $y(t)=k \sin (bt^2)$

Differentiating the above equation with respect to x, we get

y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)]

Applying chain rule,

y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)  

(c).

Finding the exact values of k and b.

As per the above parts in (a) and (b), the initial conditions are

y'(1) = 0 and y'(2) = 3

And the equations were

$y(t)=k \sin (bt^2)$

$y'(t)=kb2t\cos (bt^2)$

Now putting the initial conditions in the equation y'(1)=0

$kb2(1)\cos(b(1)^2)=0$

2kbcos(b) = 0

cos b = 0   (Since, k and b cannot be zero)

$b=\frac{\pi}{2}$

And

y'(2) = 3

$\therefore kb2(2)\cos [b(2)^2]=3$

$4kb\cos (4b)=3$

$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$

$2k\pi\cos 2 \pi=3$

2k\pi(1) = 3$  

$k=\frac{3}{2\pi}$

$\therefore b = \frac{\pi}{2} \text{ and}\  k = \frac{3}{2\pi}$

7 0
4 years ago
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