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Brilliant_brown [7]
3 years ago
8

Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Supersc

ript 6 Baseline y Superscript 11 Baseline EndFraction EndRoot? Assume x Greater-than 0 and y > 0.
Mathematics
2 answers:
MAVERICK [17]3 years ago
5 0

Answer:

\displaystyle \frac{5x}{8y^{4}}\sqrt{x}

Step-by-step explanation:

<u>Simplfy in Algebra </u>

We have the following expression

\displaystyle E=\sqrt{\frac{25x^9y^3}{64x^6y^{11}}}

Simplifying like factors in the denominator and numerator

\displaystyle E=\sqrt{\frac{25x^3}{64y^{8}}}

All the factors are perfect squares except x^3, thus we rewrite:

\displaystyle E=\sqrt{\frac{25xx^2}{64y^{8}}}

Taking the square root of all the perfect square factors:

\boxed{\displaystyle E=\frac{5x}{8y^{4}}\sqrt{x}}

blagie [28]3 years ago
4 0

Answer:

D On edge.

Step-by-step explanation:

Its Very Simple i Took it just now :D

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Question 2 Multiple Choice Worth 1 points)
umka21 [38]

Answer:

-1 or 4

Step-by-step explanation:

f(x) = g(x)

-x^2 + 4x + 12=x + 8

-x^2+3x+4=0

(x+1)(x-4)=0

x=-1,x=4

4 0
3 years ago
Solve the inequality -5(x-7)&lt;15 algebraically for x
babunello [35]

Answer:

x>4

Step-by-step explanation:

trust

3 0
2 years ago
Evaluate the square root
Alexandra [31]

\sqrt{a}=b\iff b^2=a\ for\ a\geq0\ and\ b\geq0\\\\\sqrt{\dfrac{1}{144}}=\dfrac{\sqrt1}{\sqrt{144}}=\dfrac{1}{12}\\\\\\\sqrt1=1\ because\ 1^2=1\\\\\sqrt{144}=12\ because\ 12^2=144

3 0
3 years ago
Is 13 a perfect cube , perfect square , or neither
denis-greek [22]

Answer:

neither

Step-by-step explanation:

if we cube root or square root thirteen, the result will be in decimal. So thirteen is neither a perfect square nor a perfect cube

Please mark as brainliest

5 0
3 years ago
Read 2 more answers
In a competitive examination negative marks of 2 are awarded for each wrong answers and 4 marks for every correct answer. If nee
Alex777 [14]

9514 1404 393

Answer:

  Rajan gets 6 marks more

Step-by-step explanation:

Neerav's marks are (15)(4) +(5)(-2) = 60 -10 = 50.

Rajan's marks are (14)(4) = 56.

Rajan gets 6 more marks than Neerav.

3 0
2 years ago
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