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Harlamova29_29 [7]
3 years ago
12

Which of these correctly rearranges the terms in this polynomial so like terms are next to each other?3 – 6x + 4x2 + 3x – 6x2 –

4
Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

The rearrangement of the terms is 4x^2-6x^2-6x+3x+3-4.

Step-by-step explanation:

The given expression is

3-6x+4x^2+3x-6x^2-4

Two terms are called like terms if they have same variables having same degree.

In the given expression 3 and -4, -6x and 3x, 4x² and -6x² are like terms.

Arrange the given terms according to their degree and arrange in this way so like terms are next to each other.

4x^2-6x^2-6x+3x+3-4

Therefore the rearrangement of the terms is 4x^2-6x^2-6x+3x+3-4.

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Solve the following system of equations by using the elimination method.
mariarad [96]

Answer:

the answer is (6, 1)

Step-by-step explanation:

x² + y² - 12 x - 2 y + 12 = 0

(x²-12x) +(y² -2y) +12 = 0

(x²-2(6)(x)+6²)-6² +(y² -2y+1) -1+12 = 0

(x-6)² +(y-1)² = 5²

the center of a circle is (6, 1)

4 0
3 years ago
BRAINLIEST<br>x + 4 &gt; 8. If you need to solve for x, what's the first step?
Darina [25.2K]

Answer:

the first step is subtract 4 from both sides

x + 4 > 8

x + 4 - 4 > 8 - 4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Plzzz help me with this I’ll give brainliest
scoray [572]

Answer18:

The quadrilateral ABCD is not a parallelogram

Answer19:

The quadrilateral ABCD is a parallelogram

Step-by-step explanation:

For question 18:

Given that vertices of a quadrilateral are A(-4,-1), B(-4,6), C(2,6) and D(2,-4)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-(-1)}{(-4)-(-4)}

m=\frac{7}{0}

The slope is 90 degree

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{6-6}{(-4)-(-1)}

m=\frac{0}{(-3)}

The slope is zero degree

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-4)-6}{2-2}

m=\frac{-10}{0}

The slope is 90 degree

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-(-4)}{(-4)-(2)}

m=\frac{3}{-6}

m=\frac{-1}{2}

The slope of the only line AB and CD are the same.

Thus, The quadrilateral ABCD is not a parallelogram

For question 19:

Given that vertices of a quadrilateral are A(-2,3), B(3,2), C(2,-1) and D(-3,0)

The slope of a line is given m=\frac{Y2-Y1}{X2-X1}

Now,

The slope of a line AB:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{2-3}{3-(-2)}

m=\frac{-1}{5}

The slope of a line BC:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{(-1)-2}{2-3}

m=\frac{-3}{-1}

m=3

The slope of a line CD:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{0-(-1)}{(-3)-2}

m=\frac{-1}{5}

The slope of a line DA:

m=\frac{Y2-Y1}{X2-X1}

m=\frac{3-0}{(-2)-(-3)}

m=3

The slope of the line AB and CD are the same

The slope of the line BC and DA are the same

Thus, The quadrilateral ABCD is a parallelogram

3 0
3 years ago
What is the answer for <br> three fourths x equals nine
Dmitry [639]

Answer:

x=12

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0
3 years ago
I need help making a proof for geometry! Here is the question…
MatroZZZ [7]

Answer:

Step-by-step explanation:

4 0
2 years ago
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