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Harlamova29_29 [7]
3 years ago
12

Which of these correctly rearranges the terms in this polynomial so like terms are next to each other?3 – 6x + 4x2 + 3x – 6x2 –

4
Mathematics
1 answer:
fomenos3 years ago
7 0

Answer:

The rearrangement of the terms is 4x^2-6x^2-6x+3x+3-4.

Step-by-step explanation:

The given expression is

3-6x+4x^2+3x-6x^2-4

Two terms are called like terms if they have same variables having same degree.

In the given expression 3 and -4, -6x and 3x, 4x² and -6x² are like terms.

Arrange the given terms according to their degree and arrange in this way so like terms are next to each other.

4x^2-6x^2-6x+3x+3-4

Therefore the rearrangement of the terms is 4x^2-6x^2-6x+3x+3-4.

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You have 200 items that cost $20 and you are selling them at the price of $100.
allochka39001 [22]

Your total profit is $13,000. First you bought the 200 items for $20 each. That costs $4,000. Then you sold $50 of the items at $100 each. That’s $5,000. So already you’re in the green. You’ve already made $1,000 profit. Then you sold the rest of the items at a 20% discount. 150 items multiplied by $80 is $12,000. $12,000 plus the $1,000 equals $13,000 total.

3 0
3 years ago
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Dana is tying 18 bows onto gift baskets each bow uses 4 feet of ribbon does Dana need to make all the bows
kotykmax [81]

Answer:

Dana needs 72 feet of ribbon to make all the bows

Step-by-step explanation:

If she needs to make all the bows, she needs a total of:

18 times 4 feet = 18 * 4 = 72 feet of ribbon

7 0
3 years ago
Geoff and hazel bought a new car for $25,000. The car loses approximately 15% of its value each year.
igor_vitrenko [27]

Answer:

69 tht is the answer if you work it out

Step-by-step explanation:


7 0
3 years ago
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G=x-c/x. for x<br><br>how do yoy make this an equation for x? help
zzz [600]
1.
\displaystyle \text{if }\quad G=x-  \frac{C}{x} \\\\

x \neq 0

Multiply both sides by x:

\displaystyle Gx=x\bigg(x- \frac{C}{x}\bigg )\\\\Gx=x^2-C

Subtract from both sides Gx:
Gx-Gx=x^2-C-Gx\\x^2-Gx-C=0

Then solve this equation:

\displaystyle x^2-Gx-C=0\\\\x_{1,2}= \frac{G\pm  \sqrt{G^2+4C} }{2}

2.
\displaystyle\text{if}\quad G= \frac{x-C}{x}

x \neq 0

Multiply both sides by x:

Gx=x-C

Subtract from both sides Gx:

x-C-Gx=0

Then solve this equation:

\displaystyle x-Gx-C=0\\x(1-G)=C\\x= \frac{C}{1-G}




7 0
3 years ago
Please help this is the only question im stuck on
Lemur [1.5K]
I think a, bc for the x it’s 2x and the y is +5
8 0
3 years ago
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