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3 years ago

(98 POINTS) (PLEASE HURRY!)

Mathematics

1 answer:

Montano1993 [528]3 years ago

6 0

Answer:

1. no like terms

2. x^ 3 − x^ 2 − x + 1

3.x y + x + y + 1

4.x^ 3 + x^ 2 y + x y^ 2 + y^ 3

Lol

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11Alexandr11 [23.1K]

QUESTION 33

The length of the legs of the right triangle are given as,

6 centimeters and 8 centimeters.

The length of the hypotenuse can be found using the Pythagoras Theorem.

${h}^{2} = {6}^{2} + {8}^{2}$

${h}^{2} = 36+ 64$

${h}^{2} = 100$

$h = \sqrt{100}$

$h = 10cm$

Answer: C

QUESTION 34

The triangle has a hypotenuse of length, 55 inches and a leg of 33 inches.

The length of the other leg can be found using the Pythagoras Theorem,

${l}^{2} + {33}^{2} = {55}^{2}$

${l}^{2} = {55}^{2} - {33}^{2}$

${l}^{2} = 1936$

$l = \sqrt{1936}$

$l = 44cm$

Answer:B

QUESTION 35.

We want to find the distance between,

(2,-1) and (-1,3).

Recall the distance formula,

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the values to get,

$d=\sqrt{( - 1-2)^2+(3- - 1)^2}$

$d=\sqrt{( - 3)^2+(4)^2}$

$d=\sqrt{9+16}$

$d=\sqrt{25}$

$d = 5$

Answer: 5 units.

QUESTION 36

We want to find the distance between,

(2,2) and (-3,-3).

We use the distance formula again,

$d=\sqrt{( - 3-2)^2+( - 3- 2)^2}$

$d=\sqrt{( - 5)^2+( - 5)^2}$

$d=\sqrt{25+25}$

$d=\sqrt{50}$

$d=5\sqrt{2}$

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Attached figure is the graph of a function,

f(x) = - $\sqrt{-x}$

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Therefore, Domain of the function is,

Domain : x ≤ 0 Or (-∞, 0]

And range of the function is the set of all possible output values (y-values) of the function.

Therefore, Range of the function will be,

Range : y ≤ 0 Or (-∞, 0]

Therefore, Domain and range of this function is same.

Option (3) will be the answer.

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