Answer:

Step-by-step explanation:
Let:

This is and exact equation, because:

So, define f(x,y) such that:

The solution will be given by:

Where C1 is an arbitrary constant
Integrate
with respect to x in order to find f(x,y):

Where g(y) is an arbitrary function of y.
Differentiate f(x,y) with respect to y in order to find g(y):

Substitute into 

Integrate
with respect to y:

Substitute g(y) into f(x,y):

The solution is f(x,y)=C1

Solving y using quadratic formula:
