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Leya [2.2K]
3 years ago
8

Determine the range of the function f (x) = x-4 when the domain is (1,5,6

Mathematics
1 answer:
aev [14]3 years ago
8 0

For this case we have a function of the form y = f (x). Where:

f (x) = x-4

By definition, the domain of a function is represented by the set of values of the independent variable, x, for which the value of the variable y can be calculated.

For its part, the range is represented by the values of "and".

So:

f (1) = 1-4 = -3\\f (5) = 5-4 = 1\\f (6) = 6-4 = 2

Thus, the range is {-3,1,2}

Answer:

{-3,1,2}

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Simplify -(3xy^4)^-4
Umnica [9.8K]

Answer:

\frac{-1}{81x^4y^16}

Step-by-step explanation:

<u>→Rewrite the expression so that the exponent is no longer negative. To do this, you write it as:</u>

<u />\frac{-1}{(3xy^4)^4}

<u>→Apply the exponent (4) to the 3, x, and </u>y^4:

\frac{-1}{81x^4y^16}

7 0
3 years ago
A number increase by three is two more twice the number.find the number.​
mixer [17]

Answer:

1

Step-by-step explanation:

1 increased by 3=1+3=4

Twice of 1=1+1=2

4 is two more than 2.

Therefore, the number=1

5 0
3 years ago
Kendall caught some fish two weeks ago. This amount is three less than twice the amount he caught last week.
Alchen [17]

Answer:

let Amount of fish =X

Amount is three less than twice the amount

2X - 3

Kendall caught fish = 27

Equation is

2X - 3 =27

Step-by-step explanation:

5 0
3 years ago
Work out the interior angle of the octagon.<br> Please show the working out.
bija089 [108]

Answer:

135°

Step-by-step explanation:

formula = (n-2) * 180, whereby 'n' is the number of sides.

therefore, (8-2) * 180 = 1080°

1080° ÷ number of sides

= 1080° ÷ 8

= 135°

5 0
3 years ago
Read 2 more answers
You run at a rate of 4 mph and your friend runs at a rate of 3.5 mph Your friend starts running 10 minutes before you, and you b
irga5000 [103]

Answer:

A)

<u>i) Your speed: 0.067 miles per minute</u>

<u>ii) Your friend's speed: 0.058 miles per minute</u>

<u>B) You will not catch up with your friend by the time your friend stops running.</u>

Explanation:

<u>A. Find your speed and your friend's speed in miles per minute</u>

<u>i) Your speed:</u>

You know your speed is 4 mph, which is 4 miles per hour. To find you spedd in miles per minute you must multiply by the factor that relates hours and minutes:

  • 1 hour = 60 min

  • 1 = 1 hour / 60 min

  • 4 miles / hour × 1 hour / 60 min = 4 miles / 60 min ≈ 0.0667 miles/min

         (note that the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>ii) Your friend's speed</u>

  • 3.5 miles / hour × 1 hour / 60 min = 3.5 miles / 60 min ≈ 0.0583 miles / min.

(again, the unit hour is in the denominator of the first fraction and in the numerator of the second fraction, so they cancel each other, and the final units are miles / min).

<u>B. Will you catch up with your friend by the time your friend stops running?</u>

To find whether you catch up your friend you can use a system of equation that relates the times and the distances run by each one.

i) The distance run by you is equal to your time times your speed:

  • d₁ = 0.0667 miles / min × t₁

ii) The distance run by your friend is equal to his time times his speed.

  • d₂ = 0.0583 miles / min × t₂

Since you friend started running 10 minutes before you, his time is 10 minutes more than yours, i.e. t₂ = 10 min + t₁.

Now you can write the second equation as:

  • d₂ = 0.0583 miles / min × (10 min + t₁).

And since you want to determine whether you catch up him/her by the time he/she stops running, you can determine the time when both distances would be equal:

  • d₁ = d₂

  • 0.0667 miles / min × t₁ = 0.0583 miles / min × (10 min + t₁)

To solve the equation I will ignore the units (normal procedure to solve equations):

  • 0.0667 t₁ = 0.0583 (10 + t₁)

  • 0.0667 t₁ = 0.583 + 0.0583t₁

  • 0.0667 t₁ - 0.0583 t₁ = 0.583

  • 0.0084 t₁ = 0.583

  • t₁ = 0.583 / 0.0084 ≈ 69 min

That is the time you need to catch up your friend, 69 min. Since your friend started 10 min before you and will stop after half an hour (30 min), you will not catch up with your friend before the time your friend stops running.

5 0
4 years ago
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