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Salsk061 [2.6K]
2 years ago
15

Y = 5x – 22 3x + 2y = 34

Mathematics
2 answers:
Free_Kalibri [48]2 years ago
4 0

Answer:

x = 6, y = 8

Step-by-step explanation:

y=5x-22\\3x+2y=34\\\\3x + 2(5x-22)=34\\3x + 10x - 44 = 34\\13x - 44 = 34\\13x = 78\\x = 6\\\\y = 5*6-22\\y = 30-22\\y = 8

Anika [276]2 years ago
3 0

Answer:

y = 5x – 22

3x + 2y = 34

Step-by-step explanation:

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Mike was in charge of a special sports day at the Community Center. A company donated 50 boxes of ice cream bars, with 12 bars i
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The right answer is Option D.

Step-by-step explanation:

Boxes of ice cream received = 50

Ice-creams in each box = 12

Total ice-cream bars = No. of boxes * Ice cream bars in each box

Total ice-cream bars = 12*50=600

No. of people who had ice cream bars = 520

Ice-cream bars left = Total ice cream bars - No. of people who had ice cream

Ice cream bars left = 600-520=80

80 ice cream bars were left.

The right answer is Option D.

Keywords: multiplication, subtraction

Learn more about subtraction at:

  • brainly.com/question/12896802
  • brainly.com/question/13063819

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3 years ago
There are 32 forwards and 80 guards in Leo's basketball league.
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honestly I think that if Leo included each forward to be equal then it would be 2.5 difference on each team

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Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and t
WINSTONCH [101]

Answer:

Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.  

How long will it take for this population to grow to a hundred rodents? To a thousand rodents?

Step-by-step explanation:

Use the initial condition when dp/dt = 1, p = 10 to get k;

\frac{dp}{dt} =kp^2\\\\1=k(10)^2\\\\k=\frac{1}{100}

Seperate the differential equation and solve for the constant C.

\frac{dp}{p^2}=kdt\\\\-\frac{1}{p}=kt+C\\\\\frac{1}{p}=-kt+C\\\\p=-\frac{1}{kt+C} \\\\2=-\frac{1}{0+C}\\\\-\frac{1}{2}=C\\\\p(t)=-\frac{1}{\frac{t}{100}-\frac{1}{2}  }\\\\p(t)=-\frac{1}{\frac{2t-100}{200} }\\\\-\frac{200}{2t-100}

You have 100 rodents when:

100=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{100} \\\\2t=98\\\\t=49\ months

You have 1000 rodents when:

1000=-\frac{200}{2t-100} \\\\2t-100=-\frac{200}{1000} \\\\2t=99.8\\\\t=49.9\ months

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