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Dahasolnce [82]
2 years ago
14

Janice bought her mother a bunch of 10 flowers two of the flowers are daisies one half of the remaining flowers are tulips write

the fraction of the flowers that are daisies
Mathematics
1 answer:
Vaselesa [24]2 years ago
3 0

Answer:

2/10 or 1/5 of the flowers are daises.

4/10 of the flowers are tulips.

Since there is 10 flowers, that will be your denominator. 2 out of the ten flowers, so 2 is your numerator. There is 8 flowers left over and half of that is 4.

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The product of the page numbers on two facing pages of a book is 156. Find the page numbers
Gnoma [55]

Let x be the page number then x+1 would be the other page number (because the pages are two facing pages which means they follow on consecutively)

Then

(x)(x+1) = 156

x^2 + x - 156 = 0

x = 12 or x = -13( but x can't be a negative number)

so x = 12

and the next page is 13

3 0
3 years ago
F is between E and G. EF=3X, EG= 11x-2, FG= 5x+16. Find the value of the variable
Salsk061 [2.6K]

9514 1404 393

Answer:

  x = 6

Step-by-step explanation:

The sum of segments is used:

  EF +FG = EG

  3x +(5x +16) = 11x -2 . . . . substitute given expressions

  8x +18 = 11x . . . . . . . . add 2

  18 = 3x . . . . . . . . subtract 8x

  6 = x . . . . . . divide by 3

The value of the variable is 6.

__

<em>Check</em>

The segment lengths are ...

  EF = 3x = 3·6 = 18

  FG = 5x+16 = 5·6 +16 = 46

  EG = 11x -2 = 11·6 -2 = 64 = 18+46 . . . answer is correct

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3 years ago
If someone type an average of 63 words per minute. how many word can they type in 135 minutes?
Rasek [7]
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All you have to do is to solve this problem is 60+2+0.20+0.02
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Find the equation of the exponential function represented by the table below: above^^^^
Nikitich [7]

Answer:

Step-by-step explanation:

We will use 2 coordinates from the table along with the standard form for an exponential function to write the equation that models that data. The standard form for an exponential function is

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Solving first for a:

3=a(b)^0. Sine anything in the world raised to a power of 0 is 1, we can determine that

a = 3. Using that value along with the x and y from the second coordinate I chose, I can then solve for b:

1.5=3(b)^1. Since b to the first is just b:

1.5 = 3b so

b = .5

Filling in our model:

y=3(\frac{1}{2})^x

Since the value for b is greater than 0 but less than 1 (in other words a fraction smaller than 1), this table represents a decay function.

4 0
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