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bogdanovich [222]
3 years ago
9

What is easy-access credit?

Mathematics
2 answers:
Yanka [14]3 years ago
4 0

The answer is B. Loan given for a short period of time that is not dependent on credit history

I just took the quiz and I am big brain.

lana [24]3 years ago
3 0

Answer:

b ) a loan given for a short period of time that is not dependent on credit history

Step-by-step explanation:

:) enjoy

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Find the radius of a circle with an area of 380 square inches. Round your answer to the nearest hundredth.​
sesenic [268]

Answer

Area of a circle is defined as

Area of a circle is defined asA = πr²

Area of a circle is defined asA = πr²Where

Area of a circle is defined asA = πr²WhereA is the area of the circle

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circle

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = r

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 in

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 inNearest hundredth means to 2d.p

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 inNearest hundredth means to 2d.pTherefore

Area of a circle is defined asA = πr²WhereA is the area of the circler Is the radius of the circleπ is a constant = 3.142Then,Given that the area is 380 in²So,A = πr²380 = 3.142 × r²Divide both side by 3.142380 / 3.142 = 3.142 × r² / 3.142111.372 = r²Take square root of both sides√111.372 = √r²10.5533 = rr = 10.5533 inNearest hundredth means to 2d.pThereforer = 10.55 inches

4 0
2 years ago
Read 2 more answers
I need some help with this
lapo4ka [179]

Answer:

A. 1

Step-by-step explanation:

Since it's g(-4), we have to use the first option because that means that x is equal to less than -4.

3√x + 5

3 √-4 + 5

= 1

4 0
3 years ago
What's the answer to this ?? Need help
Veseljchak [2.6K]
It goes by 3s so I think its 1.2
5 0
3 years ago
Read 2 more answers
What is the best approximation of the projection of (5,-1) onto (2,6)?
Hatshy [7]

Answer:

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

Step-by-step explanation:

We have given two points  (5, -1) and (2, 6).

Let,     \vec a=5\hat {i}-\hat {j}  and  \vec b= 2\hat {i}+6\hat{j} .

and we have calculate the projection of \vec a onto \vec b.

Now,

For the calculation of projection, first we need to calculate the dot product of  \vec a  and \vec b.

\vec a.\vec b=(5\hat {i}-\hat{j}).(2\hat{i}+6\hat{j})

     =10-6

     =4

then, we have to calculate the magnitude of \vec b.

   \mid {\vec {b}}\mid = \sqrt{2^{2}+6^{2}  } = \sqrt{40} = 2\sqrt{10}.

Now, the scalar projection of \vec a onto \vec b = \frac{\vec a.\vec b}{\mid b\mid}

                                                                 = \frac{4}{2\sqrt{10} }\frac{2}{\sqrt{10} } \times\frac{\sqrt{10} }{\sqrt{10} } =\frac{2\sqrt{10} }{10} = \frac{\sqrt{10} }{5}

and the vector projection of \vec a onto \vec b = \frac{\vec a. \vec b}{\mid\vec b \mid^{2} } . \vec b

                                                               = \frac{4}{40} . (2\hat i+ 6\hat j)

                                                                = \frac{1}{5} \hat i+\frac{3}{5} \hat j

Hence, the scalar projection of \vec a onto \vec b= \frac{\sqrt{10} }{5}, and  the vector projection of \vec a onto \vec b = \frac{1}{5} \hat i+\frac{3}{5} \hat j.

                                                               

6 0
3 years ago
To make sure that a given parallelogram is a rectangle, at least how many of its angles must measure 90?
Anna71 [15]

Answer:

The answer is 1 side must measure 90

Step-by-step explanation:


8 0
3 years ago
Read 2 more answers
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