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3 years ago

15

78 boxes of dvd, each box has 116 in it. 19 boxes are shipped, how many are left

2 answers:

yuradex [85]3 years ago

7 0

78 - 19 = 59

If you're looking for the number of boxes that are left, its 59, but if you are looking for how many DVDs are left then you would proceed to do:

116 · 59 = 6844

6844 would be the number of DVDs that are left in the remaining boxes.

guapka [62]3 years ago

3 0

I believe 6,844 dvds in total and 59 boxes left

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If a roasting is 600mm x 500mm how many 25cm cake time will fit on it?

nydimaria [60]

So assuming that 25cm is 25 square cm because you cannot have a 2 dimentional cake so

600mm by 500mm
to find the area, multiply legnth by width

mm=milimeters
cm=centimeters
this is in mm so
1cm=10mm
1mm=1/10cm
to convert from mm to cm, you divide by 10
we must divide by 10 first
legnth =600mm
600/10=60cm
legnth=60cm

width=500mm
500/10=50cm
width=50cm

area=60 times 50=3000 square cm or cm^2
so 3000 is the area
25 is the area of each cake
divide 3000 into 25 and find how many cakes will fit

3000/25=120

120 cakes will fit

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3 years ago

Find the slope of the line that passes through<br> the points (-6, -2) and (-7, -2)

xxTIMURxx [149]

Answer:

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Step-by-step explanation:

-2+3/-7+6

o/-1

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as slope is y2-y1/

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3 years ago

1489.45 Round this number to two decimal places

Gekata [30.6K]

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8 0

2 years ago

Read 2 more answers

Write the expression as a power

Natasha_Volkova [10]

The expression given in the question is expressed as a power is x^10

According to the law of indices, multiplication of powers becomes addition as shown:

$a^m \times a^n = a^{m+n}$

Given the following expressions;

$xx^4x^4x$

This can also be expressed as:

$= x \times x^4 \times x^4 \times x\\= x^{1+4+4+1}\\=x^{5+5}\\=x^{10$

This shows that the expression as power is x^10

Learn more here: brainly.com/question/20298728

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2 years ago

Two litters of a particular rodent species have been born; first with two brownhaired and one gray-haired (litter 1) and the oth

maks197457 [2]

Answer:

The probability that the animal chosen is brown-haired is 0.6333.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> : a brown-haired rodent

<em>B</em> : Litter 1

The information provided is:

$P (A|B) =\frac{2}{3}\\\\P(A|B^{c})=\frac{3}{5}$

The probability of selecting any of the two litters is equal, i.e.

$P(B)=P(B^{c})=\frac{1}{2}$

According to the law of total probability:

$P(X)=P(X|Y_{1})P(Y_{1})+P(X|Y_{2})P(Y_{2})+...+P(X|Y_{n})P(Y_{n})$

Compute the total probability of event <em>A</em> as follows:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

$=[\frac{2}{3}\times\frac{1}{2}]+[\frac{3}{5}\times\frac{1}{2}]\\\\=\frac{1}{3}+\frac{3}{10}\\\\=\frac{10+9}{30}\\\\=\frac{19}{30}\\\\=0.6333$

Thus, the probability that the animal chosen is brown-haired is 0.6333.

5 0

2 years ago