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allsm [11]
3 years ago
13

A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 45.0 and 55.

0 minutes. Find the probability that a given class period runs between 50.75 and 51.75 minutes.
Mathematics
1 answer:
Crank3 years ago
8 0
In this problem, we are given a 10-minute range, from 45 to 55 minutes. The question is asking for a 1-minute range, 50.75 to 51.75 minutes. A 1-minute range out of a total 10-minute range gives us 1/10 chance, or 10% probability.
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Martha estimated there were 96 marbles in a jar for a contest. The actual number of marbles in the jar was 118. What was the per
matrenka [14]
To find percent error, you subtract the actual number from your estimate, take the absolute value, and divide by the actual number.

l 96 - 118 l
l -22 l
l 22 l
l 22 l / 118
0.19%  (this was rounded)

Hope this helps!
3 0
3 years ago
Chase use 1/6 cup of bananas for every 2/3 cup of apples to make a smoothie. Enter the number of cups of bananas Vhase uses for
Reika [66]

Answer:

1/4 cup of bananas

Step-by-step explanation:

1/6 cup of bananas = 2/3 cup of apples

1/6 cup of bananas = 4/6 cup of apples

1/24 (1/6 ÷ 4 since 4/6 cup of apples is 4 units and we need 1 unit) cup of bananas = 1/6 cup of apples

1 cup of apples = 1/4 (1/24 x 6 for 6 units) cup of bananas

4 0
3 years ago
Select the correct answer.
Volgvan

Answer:

B

Step-by-step explanation:

If C is the correct answer and if the final result is multiplied out, where does the minus sign in a^4 - b^4 come from? All pluses don't make a minus. A is incorrect.

If D is correct, then a^2 - b^2 should be further factored producing a different kind of answer, like (a + b)^2(c-d)^2 which is not the same as a^4 - b^4. So D is not correct.

The first step in factoring a^4 - b^4 is (a^2 + b^2)(a^2 - b^2) A doesn't lead you anywhere. A is incorrect. The answer must be B.

a^4 - b^4 = (a^2 -  b^2)(a^2 + b^2)  The first term factors.

a4 - b^4 = (a + b)(a - b) (a^2 +b^2)

4 0
3 years ago
Suppose you have a random variable that is uniformly distributed between 7 and 26. what is the expected value for this random va
Daniel [21]
\mathbb E(X)=\int_7^{26}\dfracx{26-7}\,\mathrm dx=\dfrac{33}2=16.5

which follows from the definition for expected value,

\mathbb E(X)=\int_{-\infty}^\infty xf_X(x)\,\mathrm dx

where f_X(x) is the probability density function for X.
4 0
3 years ago
Simplify: (-14 (-67 (28)
Vesna [10]

Answer:

26,264

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
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