Im gona assume you mean
f(x) = 3x + 2 + 8x + 4. Add like-terms
Y = 11x + 6
0= 11x + 6
-6 = 11x
X= -6/11
f<span>(x)</span>=<span>x^2</span>−<span>6
</span>Replace <span>f<span>(x)</span></span> with <span>yy</span>.
<span>y=<span>x^2</span>−<span>6
</span></span>Interchange the variables.
<span>x=<span>y2</span>−6
</span>Solve for <span>yy</span><span>.
</span>
Move <span><span>−6</span><span>-6</span></span> to the right side of the equation by subtracting <span><span>−6</span><span>-6</span></span> from both sides of the equation.<span><span><span>y2</span>=6+x</span><span><span>y2</span>=6+x</span></span>Take the <span><span>square</span><span>square</span></span> root of both sides of the <span><span>equation</span><span>equation</span></span> to eliminate the exponent on the left side.<span><span>y=±<span>√<span>6+x</span></span></span><span>y=±<span>6+x
</span></span></span>The complete solution is the result of both the positive and negative portions of the solution.
Tap for more steps...
<span>y=<span>√<span>6+x</span></span>,−<span>√<span>6+x</span></span></span>
Solve for y<span> and replace with </span><span><span>f^<span>−1</span></span><span>(x).
</span></span>
<span>Answer is f<span>−1</span></span><span>(x)</span>=<span>√<span>6+x</span></span>,−<span>√<span>6+<span>x</span></span></span>
1.solve for y
2x+4y=12
<u> </u><span><u> -2x -2x</u>
</span><u>4y</u>=<u>12-2x</u>
<u>4 4</u>
y=3-1/2x
step2 plug in y and solve for x
2x+8y=24
2x+8(3-1/2x)= 24
2x+24-4x=24
<u>-2x</u>=<u>0
</u><u>-2 -2</u>
x=0
last step plug in x and solve for y
y=3-1/2x(0)
y=3
Answer:9/4
Step-by-step explanation:
99/8*2/11=9/4*1/1=9/4
You can cancel out 99 and 11 to 9 and 1 as they are multiples of eac hother and you can do the same for 8 and 2 to 4 and 1
