X = 6 , y = -2
hope this helps
Answer:
x = -1 or x = -3
Step-by-step explanation:
x + 3/x = -4
x² + 3 = -4x
x² + 4x + 3 = 0
(x + 1) (x + 3) = 0
x = -1 or x = -3
check: (-1) + (3/-1) = -1 - 3 = -4
(-3) + (3/(-3)) = -3 -1 = 14
Answer:
a) 8.13
b) 4.10
Step-by-step explanation:
Given the rate of reaction R'(t) = 2/t+1 + 1/√t+1
In order to get the total reaction R(t) to the drugs at this times, we need to first integrate the given function to get R(t)
On integrating R'(t)
∫ (2/t+1 + 1/√t+1)dt
In integration, k∫f'(x)/f(x) dx = 1/k ln(fx)+C where k is any constant.
∫ (2/t+1 + 1/√t+1)dt
= ∫ (2/t+1)dt+ ∫ (1/√t+1)dt
= 2∫ 1/t+1 dt +∫1/+(t+1)^1/2 dt
= 2ln(t+1) + 2(t+1)^1/2 + C
= 2ln(t+1) + 2√(t+1) + C
a) For total reactions from t = 1 to t = 12
When t = 1
R(1) = 2ln2 + 2√2
≈ 4.21
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
R(12) - R(1) ≈ 12.34-4.21
≈ 8.13
Total reactions to the drugs over the period from t = 1 to t= 12 is approx 8.13.
b) For total reactions from t = 12 to t = 24
When t = 12
R(12) = 2ln13 + 2√13
≈ 12.34
When t = 24
R(24) = 2ln25 + 2√25
≈ 16.44
R(12) - R(1) ≈ 16.44-12.34
≈ 4.10
Total reactions to the drugs over the period from t = 12 to t= 24 is approx 4.10
Queremos ver que fracción de la finca se ha destinado a plazas de aparcamiento.
La solución es:
La fracción de la finca que se destina a plaas de aparcamiento es 3/56
Sabemos que originalmente se iba a destinar 3/14 del total de la finca a plazas de aparcamiento, pero finalmente se destino 3/4 de lo previsto a zonas ajardinadas.
Es decir, <u>se destino 3/4 de los 3/14 del total de la finca</u> a zonas ajardinadas, entonces <u>el 1/4 restante se dedico a plazas de aparcamiento</u>, esto da:
(1/4)*3/14 = 3/56
La fracción de la finca que se destina a plaas de aparcamiento es 3/56
Sí quieres aprender más, puedes leer:
brainly.com/question/16649102
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