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insens350 [35]
3 years ago
7

6. Solve the equation x2 = 80.

Mathematics
2 answers:
ehidna [41]3 years ago
7 0

Answer:

x=4√5

Step-by-step explanation:

jonny [76]3 years ago
4 0

Answer:

40

Step-by-step explanation:

80/2=40

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Curtis earns a weekly salary of $300. He also earns a commission of 4% on all of his sales. What is the minimum dollar amount of
jonny [76]

Answer:

put four percent in decimal form and divide that by 300

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
I need help please!
Vlad1618 [11]

Answer:

\Huge \boxed{y=3x+6}

Step-by-step explanation:

y = mx + b

m = slope

b = y-intercept

The slope can be found from two points.

\displaystyle m=\frac{y_2-y_1}{x_2-x_1}

The two points from the graph are (1, 9) and (2, 12).

Plugging in the values and evaluating.

\displaystyle m=\frac{12-9}{2-1}

\displaystyle m=\frac{3}{1}

m=3

The slope of the line is 3.

The y-intercept of the line is where the line cross the y-axis.

The line crosses the y-axis at (0, 6).

b=6

The slope-intercept form of the line is:

y=3x+6

8 0
3 years ago
Suppose that Upper X has a discrete uniform distribution f left-parenthesis x right-parenthesis equals StartLayout left-brace1st
emmasim [6.3K]

Answer:

the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444

Step-by-step explanation:

Given the data in the question;

x        f(x)         xp(x)               x²p(x)

1         1/3        0.33333        0.33333

2        1/3        0.66667        1.33333

3        1/3        1.00000        3.0000

∑                    2.0000          4.6667

∑(xp(x)) = 2

∑(x²p(x)) = 4.6667

Variance σ² = ∑(x²) - ∑(x)² = 4.6667 - (2)² = 4.6667 - 4 = 0.6667

standard deviation σ = √variance = √0.6667 = 0.8165

Now since, n = 33 which is greater than 30, we can use normal approximation

for normal distribution z score ( x-μ)/σ

mean μ = 2

standard deviation = 0.817

sample size n = 33

standard of error σₓ = σ/√n = 0.817/√33 = 0.1422

so probability will be;

p( 2.1  < X < 2.4 ) = p(( 2.1-2)/0.1422) <  x"-μ/σₓ  <  p(( 2.4-2)/0.1422)

= 0.70 < Z < 2.81    

=  1 - ( 0.703 < Z < 2.812 )

FROM Z-SC0RE TABLE

=  1 - ( 0.25804 + 0.49752 )

= 1 - 0.75556

p( 2.1  < X < 2.4 ) = 0.2444

Therefore,  the probability that the sample mean is greater than 2.1 but less than 2.4 is 0.2444

7 0
3 years ago
Tom determines the system of equations below has two solutions, one of which is located at the vertex of the parabola.
Rus_ich [418]

Answer:

b must equal 7 and a second solution to the system must be located at (2, 5).

Step-by-step explanation:

Rearranging the first equation:

y = (x - 3)^2 + 4

From this we see that the vertex is at the point (3,4).

So one solution of equation 2 is (3 ,4).

Substituting in equation 2:

4 = -3 + b

b = 7.

So equation 2 is y = - x + 7.

Now we check if  (2, 5) is on this line:

5 = -2 + 7 = 5 , therefore  (2, 5) is on this line.

Verifying if (2, 5)  is also on y = (x - 3)^2 + 4:

5 = (2 - 3)^2 + 4 =  1 + 4 = 5

- so it is. and a second solution to the system is (2, 5).

5 0
2 years ago
How to solve algebraic equations with 2 variables
melisa1 [442]
You re write the equation, so when the equations are added one of the variables are eliminated
8 0
2 years ago
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