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IrinaK [193]
3 years ago
9

Select the correct adjective form for the following sentence.

Mathematics
2 answers:
Vlad [161]3 years ago
5 0

Answer: The correct answer is able

Step-by-step explanation: from the options presented the other comparatives and superlatives if used are grammatically incorrect the only correct form is the word able

Abler and ablest are comparative and superlative of the word able

MissTica3 years ago
3 0
Who here is able to lift 2,500 pounds?
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2x^3-x^2-3x=210<br> the answer is 5 but I want to know why.
mel-nik [20]

Answer:

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

Step-by-step explanation:

1) Move all terms to one side.

2x^{3} -x^{2} -3x-210=0

2) Factor 2{x}^{3}-{x}^{2}-3x-210 using Polynomial Division.

1 -  Factor the following.

2x^{3} -x^{2} -3x-210

2 -  First, find all factors of the constant term 210.

1,2,3,4,5,6,7,10,14,15,21,30,35,42,70,105,210

3) Try each factor above using the Remainder Theorem.

Substitute 1 into x. Since the result is not 0, x-1 is not a factor..

2*1^{3} -1^{2} -3*1-210=-212

Substitute -1 into x. Since the result is not 0, x+1 is not a factor..

2(-1)^{3} -(-1)^{2} -3*-1-210=-210

Substitute 2 into x. Since the result is not 0, x-2 is not a factor..

2*2^{3} -2^{2} -3*2-210=-204

Substitute -2 into x. Since the result is not 0, x+2 is not a factor..

2{(-2)}^{3}-{(-2)}^{2}-3\times -2-210 = -224

Substitute 3 into x. Since the result is not 0, x-3 is not a factor..

2\times {3}^{3}-{3}^{2}-3\times 3-210 = -174

Substitute -3 into x. Since the result is not 0, x+3 is not a factor..

2{(-3)}^{3}-{(-3)}^{2}-3\times -3-210 = -264

Substitute 5 into x. Since the result is 0, x-5 is a factor..

2\times {5}^{3}-{5}^{2}-3\times 5-210 =0

------------------------------------------------------------------------------------------

⇒ x-5

4)  Polynomial Division: Divide 2{x}^{3}-{x}^{2}-3x-210  by x-5.

                                               2x^{2}                       9x                      42

                                      -------------------------------------------------------------------------

x-5                               |    2x^{3}                          -x^{2}                     -3x     -210

                                           2x^{3}                             -10x^{2}

                                        -----------------------------------------------------------------------

                                                                             9x^{2}                -3x       -210

                                     --------------------------------------------------------------------------

                                                                          42x                              -210

                                                                         42x                               -210

                                      -------------------------------------------------------------------------

5)  Rewrite the expression using the above.

2x^2+9x+42

(2x^2+9x+42)(x-5)=0

3) Solve for x.

x=5

4)  Use the Quadratic Formula.

1 - In general, given a{x}^{2}+bx+c=0 , there exists two solutions where:

x=\frac{-b+\sqrt{b^{2} -4ac} }{2a} ,\frac{-b-\sqrt{b^2-4ac} }{2a}

2 -  In this case, a=2,b=9 and c = 42.

x=\frac{-9+\sqrt{9^2*-4*2*42} }{2*2} ,\frac{-9-\sqrt{9^2-4*2*42} }{2*2}

3 - Simplify.

x=\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

5) Collect all solutions from the previous steps.

x=5,\frac{-9+\sqrt{255}i }{4} ,\frac{-9-\sqrt{255}i }{4}

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2 years ago
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  (c) $72

Step-by-step explanation:

Each tile is 8/12 ft = 2/3 ft on a side. Then 8/(2/3) = 12 tiles will fit along each edge of the square area to be tiled. That is ...

  12 × 12 = 144

tiles will be needed to cover the area.

The cost of 144 tiles at $0.50 each is ...

  (144)($0.50) = $72.00

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