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zheka24 [161]
3 years ago
14

A tutor charges $30 for 2 hours. how much does she charge for 5 hours

Mathematics
2 answers:
lukranit [14]3 years ago
6 0
She charges $15 for 1 hour. For a total of 5 hours, she charges $75. $75 is the answer.
vesna_86 [32]3 years ago
5 0
$30/2=$15.
She charges $15 for one hour
Therefore, she must charge $75 for 5 hours
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Tom has read 2 books for school. Tom read 1/2 of the first book on Thursday and 5/12 of the second book on Friday. What total fr
Mandarinka [93]

Answer:

35/12

Step-by-step explanation:

1 1/2+1 5/12

=3/2+17/12

=3*6+17*1/12

=18+17/12

=35/12

3 0
3 years ago
Really didn’t understand this Can someone please help?
Vaselesa [24]

Answer:

125

Step-by-step explanation:

because it is the next side of x

7 0
3 years ago
Read 2 more answers
-4,11)(-9,6)<br><br> Find x and y intercepts!! show work plzzz
iren [92.7K]

Answer:

(-15, 0) --> x intercept

(0, 15) --> y intercept

Step-by-step explanation:

First, you need to find the equation of the line:

gradient equals 1 --> (6 - 11)/(-9 - (-4))

y = x + c

sub point (-9, 6)

6 = -9 + c

c = 6 + 9

c = 15

Equation of line: y = x + 15

x-intercept is when y = 0

0 = x + 15

x = -15 (that's the x-intercept)

(-15, 0)

y-intercept is when x = 0

y = 0 + 15

y = 15 (this is the y-intercept). The y-intercept is also the contant 'c'

(0, 15)

5 0
3 years ago
How much does Juana have in liquid assets if her car is worth $5,500 and she has
JulsSmile [24]

Answer:

1993

Step-by-step explanation:

Something is liquid if you can easily convert it into cash

So something like a car is not liquid (because it takes time to sell the car)

but something like a checking account is liquid (because it's easy to widthdraw your money)

so we have

1310+683= 1993

5 0
3 years ago
At a school with 100? students, 33 were taking? Arabic, 32 ?Bulgarian, and 40 Chinese. 9 students take only? Arabic, 12 take onl
Stels [109]

Answer: The answer is 4 and 32.

Step-by-step explanation: Let "A", "B" and "C" represents the set of students who were taking Arabic, Bulgarian and Chinese respectively.

The, according to the given information, we have

n(A)=33,~~n(B)=32,~~n(C)=40,~~n(A\cap B)=14.

Let 'p' represents the number of students who take all the three languages, then

n(A\cap B\cap C)=p.

Also,

n(A)-n(A\cap B)-n(A\cap C)+n(A\cap B\cap C)=9\\\\\Rightarrow n(A\cap B)+n(A\cap C)=24+p~~~~~~~~~~~~~~(a),\\\\n(A\cap B)+n(B\cap C)=20+p~~~~~~~~~~~~~~(b),\\\\n(B\cap C)+n(A\cap C)=20+p~~~~~~~~~~~~~~~(c).

From here, we get after subtracting equation(c) from (b) that

n(A\cap B)=n(A\cap C)=14.

Therefore,

p=14+14-24=4, and from equation (a), we find

n(B\cap C)=24-14=10.

Thus,

n(A\cap B\cap C)=4 and

n(A\cup B\cup C)=n(A)+n(B)+n(C)-n(A\cap B)-n(B\cap C)-n(A\cap C)+n(A\cap B\cap C)\\\\\Rightarrow n(A\cap B\cap C)=33+32+40-9-12-20+4\\\\\Rightarrow n(A\cap B\cap C)=68.

Thus, the number of students who take all the three languages is 4 and the number of students who take none of the languages is 100-68 = 32.

5 0
3 years ago
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