Answer:
Jesse needs to work 43 hours in the month to make $400 and $60
work for answer: 9.50 x 43 = 408.5
example why it can't be lower or higher than 43 hours 9.50 x 42 = 399 or 9.50 x 44 = 418
Are you solving p or h
This is the answer for h h=p-1/2
This is the answer for p p=h+1/2
Answer:
1/64
Step-by-step explanation:
4x4^3/4^7
4^-3
1/4^3
<u>1/64</u>
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Let's first establish what we already know for this problem.
x = total number of hotdogs sold
y = total profit from total sales of hotdogs
Let's also establish the other equations which we will require in order to solve this problem.
Equation No. 1 -
Profit for 40 hotdogs = $90 profit
Equation No. 2 -
Profit for 80 hotdogs = $210 profit
STEP-BY-STEP SOLUTION
From this, we can use the formula y = mx + b & substitute the values for x & y from one of the two previous equations into the formula in order to obtain the values of m & b for the final equation. Here is an example of the working out as displayed below:
Firstly, using the first or second equation, we make either m or b the subject. Here I have used the first equation and made m the subject:
Equation No. 1 -
y = mx + b
90 = m ( 40 ) + b
40m = 90 - b
m = ( 90 - b ) / 40
Now, make b the subject in the second equation as displayed below:
Equation No. 2 -
y = mx + b
210 = m ( 80 ) + b
210 = 80m + b
b = 210 - 80m
Then, substitute m from the first equation into the second equation.
Equation No. 2 -
b = 210 - 80m
b = 210 - 80 [ ( 90 - b ) / 40 ]
b = 210 - [ 80 ( 90 - b ) / 40 ]
b = 210 - 2 ( 90 - b )
b = 210 - 180 - 2b
b - 2b = 30
- b = 30
b = - 30
Now, substitute b from the second equation into the first equation.
Equation No. 1 -
m = ( 90 - b ) / 40
m = ( 90 - ( - 30 ) / 40
m = ( 90 + 30 ) / 40
m = 120 / 40
m = 3
Through this, we have established that:
m = 3
b = - 30
Therefore, the final equation to model the final profit, y, based on the number of hotdogs sold, x, is as follows:
y = mx + b
y = ( 3 )x + ( - 30 )
ANSWER:
y = 3x - 30
Answer:

Step-by-step explanation:
<u>step(i)</u>
Given function y = 3 x³ - 2 x ... (i)
Differentiating equation (i) with respective to 'x'

Given x = -2


<u><em>Step(ii):-</em></u>
<u><em>we know that </em></u>

Given 

substitute values
⇒ 
cross multiplication , we get

<u><em>Final answer</em></u>:-
