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4 years ago

Enter the amplitude of the function f(x) . f(x) = 5 sin x

Mathematics

1 answer:

mariarad [96]4 years ago

6 0

Answer:

Step-by-step explanation:

The amplitude is the distance from the highest to lowest points divided that by 2.

Or the simpliest way when given the function

f(x) = A sin(x)

Where A is the amplitude

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Anton's family drove 216 mi to the lake averaging 48 mi/hmi/h . On the return trip home they averaged 54 mi/hmi/h .

saul85 [17]

Answer:

Option B is correct.

Total time that Antony's family spent driving to and from the lake = 8.5 hr

Step-by-step explanation:

Using time formula:

$Time = \frac{Distance}{Speed}$

As per the given statement: Anton's family drove 216 mi to the lake averaging 48 mi/hr .On the return trip home they averaged 54 mi/hr

⇒ Anton's family drove total distance = 216 mi

Speed of Antony's family driving to lake = 48 mi/hr

Time taken to driving to lake = $\frac{216}{48} = 4.5 hr$

Now,

Speed of Antony's family driving from lake = 54 mi/hr

Time taken to driving from lake = $\frac{216}{54} = 4 hr$

Total time spent driving to and from the lake = 4 + 4.5 = 8.5 hr.

therefore, the total time that Antony's family spent driving to and from the lake was, 8.5 hr

8 0

4 years ago

Read 2 more answers

Which equation describes a linear function? a) y = 3x + 5, b) y = -x^2 -5 , c) y = 3/x, d) y = x^3

s344n2d4d5 [400]

Answer:

A Linear function is an equation whose graph is a straight line. It has the following form; y = a + bx.

A linear function contains one independent variable and one dependent variable. X is the independent variable and y is the dependent variable.

The answer is a) y = 3x + 5

4 0

3 years ago

Read 2 more answers

Find the vertices and foci of the hyperbola with equation quantity x minus five squared divided by eighty one minus the quantity

Papessa [141]

If you notice, the positive fraction, is the one with the "x" variable in it, that simply means, the hyperbola is opening over the x-axis, so is a horizontal one, therefore

$\bf \textit{hyperbolas, horizontal traverse axis }
\\\\
\cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h\pm a, k)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------$

$\bf \cfrac{(x-5)^2}{81}-\cfrac{(y-1)^2}{144}=1\implies \cfrac{(x-5)^2}{9^2}-\cfrac{(y-1)^2}{12^2}=1~~
\begin{cases}
a=9\\
b=12
\end{cases}
\\\\\\
c=\sqrt{9^2+12^2}\implies c=15\\\\
-------------------------------\\\\
vertices~~(5\pm 9,1)\implies 
\begin{cases}
(14,1)\\
(-4,1)
\end{cases}~~foci~~(5\pm 15,1)\implies 
\begin{cases}
(20,1)\\
(-10,1)
\end{cases}$

3 0

3 years ago

1) −6k + 7k 2) 12r − 8 − 12 3) n − 10 + 9n − 3 4) −4x − 10x

crimeas [40]

Step-by-step explanation:

I assume we are simplifying

1) -6k+7k = k

2) 12r-8-12 = 12r-20

3) n-10+9n-3 = 10n-13

4) -4x-10x = -14x

7 0

2 years ago

which of the following are valid probability distributions for a discrete random variable? check all that apply

djverab [1.8K]

A. 0.16 + 0.193 + 0.222 + 0.233 + 0.067 + 0.125 = 84
probabilities are all between 0 and 1 but does not add to 1.
B. 0.35+0.18+ 0.21+ 0.06+ 0.17+ 0.03 = 1
probabilities are all between 0 and 1 and also add to 1.
C. (0.01) 11+ (0.01) 12+ (0.01) 13 = 0.11+0.12+0.13 =0.36
probabilities are all between 0 and 1 but does not add to 1.
D. 0.16+0.12+ 0.02+ 0.08+ 0.22+ 0.05+ 0.15+ 0.02+ 0.18 = 1
probabilities are all between 0 and 1 and also add to 1.
E. 0.12-0.02+0.18+0.08+0.15+0.05+0.16+0.27+0.02+ 0.36 -0.15 -0.22 =1
probabilities are all between 0 and 1 and also add to 1.

3 0

4 years ago

Read 2 more answers