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oksano4ka [1.4K]
3 years ago
8

AABC is isosceles. AB = 3x - 4 and BC = 5x - 10. AB = [?]

Mathematics
1 answer:
Schach [20]3 years ago
4 0

If AB = BC then set up the equation 3x - 4 = 5x - 10

Subtract 3x.

-4 = 2x - 10

Add 10.

6 = 2x

Divide by 2.

3 = x

AB is 3x - 4 so

3(3) - 4

9 - 4

5.

AB = 5

If AB is not equal to BC then this is not solvable.

But if they are I am sure AB = 5.

Hope this helps

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A square has a side length of 3x3y5. What is the area of the square?​
kotykmax [81]

Answer:

9x^3 y^5

Step-by-step explanation:

Since the formula to finding area is (L*W = A), we first have to find the width.

Width: 3x^3 y^5 times 2 = 6x^3 y^5

Then we add them. So, 3x^3 y^5 + 6x^3 y^5 = 9x^3 y^5

8 0
3 years ago
100 equals 15 minus a number all divided by 5 A) x = 17 <br>B) x = -485<br>C) x = 33 <br>D) x=-17​
siniylev [52]
A

Hope this helps


Mark brainliest please
8 0
3 years ago
Brian invests ?1900 into a savings account. The bank gives 3.5% compound interest for the first 2 years and 4.9% thereafter. How
Scorpion4ik [409]

let's check how much is it after 2 years firstly.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &1900\\ r=rate\to 3.5\%\to \frac{3.5}{100}\dotfill &0.035\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &2 \end{cases} \\\\\\ A=1900\left(1+\frac{0.035}{1}\right)^{1\cdot 2}\implies A=1900(1.035)^2\implies A=2035.3275


Brian invested the money for 6 years, so now let's check how much is that for the remaining 4 years.


\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &2035.3275\\ r=rate\to 4.9\%\to \frac{4.9}{100}\dotfill &0.049\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{yearly, thus once} \end{array}\dotfill &1\\ t=years\dotfill &4 \end{cases}


\bf A=2035.3275\left(1+\frac{0.049}{1}\right)^{1\cdot 4}\implies A=2035.3275(1.049)^4 \\\\\\ A\approx 2464.54\implies \boxed{\stackrel{\textit{rounded up }}{A=2465}}

4 0
3 years ago
The graph of f(x) = |x| is transformed to g(x) = |x + 1| – 7. On which interval is the function decreasing?
timofeeve [1]

Answer:

g is decreasing for all x less than or equal to -1

Step-by-step explanation:

The graph of the function y = |x| looks like a "vee."

g(x) = |x + 1| - 7 moves that graph 1 unit to the <u>left</u><em> </em>(I know, it looks backwards!) and down 7 units. See attached image.

Function g(x) is decreasing for all x \le -1.

5 0
3 years ago
Read 2 more answers
What is 10^-3 in math
Alborosie
It is 1/1000 or 1/10∧-3
that is because whenever there is a negative exponent put it as the denominator and the numerator by default, if there isn't any, should be one. 
so put it under and then figure it out
5 0
3 years ago
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