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3 years ago

AABC is isosceles. AB = 3x - 4 and BC = 5x - 10. AB = [?]

Mathematics

1 answer:

Schach [20]3 years ago

4 0

If AB = BC then set up the equation 3x - 4 = 5x - 10

Subtract 3x.

-4 = 2x - 10

Add 10.

6 = 2x

Divide by 2.

3 = x

AB is 3x - 4 so

3(3) - 4

9 - 4

AB = 5

If AB is not equal to BC then this is not solvable.

But if they are I am sure AB = 5.

Hope this helps

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Write an equation for when slope =-3 and y-intercept = 36

Elenna [48]

Answer:

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Step-by-step explanation:

the slope is -3, so just add an x.

the y intercept is 36

put them a together and you get -3x+36

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3 years ago

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3 years ago

If y varies jointly as x and z and y = 4 when x = 2 and z = 3, what is y when x = -6 and z = 2?

sp2606 [1]

Answer:

Step-by-step explanation:

Y = kxz

Putting values of y x and z in the equation

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3 years ago

Suppose a researcher is testing the hypothesis Upper H 0: pequals0.4 versus Upper H 1: pless than0.4 and she finds the P-valu

andre [41]

Answer:

D. If the P-value for a particular test statistic is 0.33, she expects results at least as extreme as the test statistic in exactly 33 of 100 samples if the null hypothesis is true.

D. Since this event is not unusual, she will not reject the null hypothesis.

Step-by-step explanation:

Hello!

You have the following hypothesis:

H₀: ρ = 0.4

H₁: ρ < 0.4

Calculated p-value: 0.33

Remember: The p-value is defined as the probability corresponding to the calculated statistic if possible under the null hypothesis (i.e. the probability of obtaining a value as extreme as the value of the statistic under the null hypothesis).

In this case, you have a 33% chance of getting a value as extreme as the statistic value if the null hypothesis is true. In other words, you would expect results as extreme as the calculated statistic in 33 about 100 samples if the null hypothesis is true.

You didn't exactly specify a level of significance for the test, so, I'll use the most common one to make a decision: α: 0.05

Remember:

If p-value ≤ α, then you reject the null hypothesis.

If p-value > α, then you do not reject the null hypothesis.

Since 0.33 > 0.05 then I'll support the null hypothesis.

I hope it helps!

3 0

3 years ago

In a random sample of 74 women at a company, the mean salary is $39,902 with a standard deviation of $3270 in a random sample of

ValentinkaMS [17]

The correct answer is the first choice, ($1818.30, $5077.70.)

To find this, we first find the z-score based on the confidence level:
Convert 95% to a decimal: 95%=95/100 = 0.95
Subtract from 1: 1-0.95 = 0.05
Divide by 2: 0.05/2 = 0.025
Subtract from 1: 1-0.025 = 0.975

Using a z-table (http://www.z-table.com) we see that this value is associated with a z-score of 1.96.

Next, we identify
$\overline{x_1}=39902; \overline{x_2}=36454; n_1=74; n_2=40; \sigma_1=3270; \sigma_2=4677$

Next we find
$(\overline{x_1}-\overline{x_2})=(39902-36454) = 3448$

Next we find
$\sqrt{\frac{\sigma_1^2}{n_1}+\frac{\sigma_2^2}{n_2}}
\\
\\=\sqrt{\frac{3270^2}{74}+\frac{4677^2}{40}}=\sqrt{\frac{10692900}{74}+\frac{21874329}{40}}
\\
\\=831.479$

Next, we multiply this value by z:
1.96(831.479) = 1629.70

The confidence interval is given by
$3448\pm1629.70
\\
\\=(3448-1629.70, 3448+1629.70)
\\
\\=(1818.30, 5077.70)$

5 0

3 years ago