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Salsk061 [2.6K]
3 years ago
6

Solve the system or linear equations

Mathematics
1 answer:
Vanyuwa [196]3 years ago
8 0

Answer:

37. {-1, -1}.

Step-by-step explanation:

I'll solve the first one . The other can be solved in a similar way. We can use the method of elimination.

x1 - x2 = 0

3x1 - 2x2 = -1

We can multiply the first equation by -2. We then have an equation containing + 2x2 so when we add this to the second equation the 2x2 will be eliminated

So the first equation becomes:

-2x1 + 2x2 = 0     Bring down the second equation:

3x1 - 2x2 = -1       Now adding, we get:

x1 + 0 = -1

so x1 = -1.

Now we substitute this value of x1 in the original first equation:

-1 - x2 = 0

-1 = x2

x2 = -1.

So the solution set is {-1, -1}.

If there are more than 2 equations you can use a combination of substitutions and eliminations.

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The loudness, L, measured in decibels (Db), of a sound intensity, I, measured in watts per square meter, is defined as L = 10 lo
Inessa [10]

Answer:

50 Db

Step-by-step explanation:

we know that

The loudness in decibels is given by the formula

L = 10log(\frac{I}{I_0})

where

I  = sound intensity in watts per square meter (Watts/m^2)

I₀ = reference intensity, = 10^(-12) Watts/m^2

so

For I=10^(-7) Watts/m^2

substitute in the formula above and solve for L

L = 10log(\frac{10^{-7} }{10^{-12}})

L = 10log(10^{5})

L = 10 (5)=50\ Db

7 0
3 years ago
Read 2 more answers
What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?
Natali5045456 [20]

Answer:

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

x-6y=42    ..................Given

which can be written as

y=mx+c

Where m is the slope of the line

∴ y=\dfrac{x}{6}-7

On Comparing we get

Slope = m = \dfrac{1}{6}

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

m\times m_{1}=-1\\Substituting\ m\\ \dfrac{1}{6} m_{1}=-1\\\\m_{1}=-6

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

(y-y_{1})=m(x-x_{1})

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

(y-7)=-6(x--2)=-6(x+2)=-6x-12\\\\\therefore 6x+y=-5.......is\ the required\ equation\ of\ the\ line

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

6x+y=-5

3 0
3 years ago
Fill in the blank space<br> z2 + 5z – 36 = (z – 4)(z +_)
labwork [276]
Answer=9

To solve this, we just have to find a number that, when added to -4, make a total of 5, and when multiplied by -4 make a total of -36.

x+-4=5

x*-4=-36

9 fits the parameters for both of these

9+-4=9
9-4=5
5=5

9*-4=36
36=36
8 0
4 years ago
25 liters of water are pumped into a dam in 20 seconds
elena-14-01-66 [18.8K]

1 minute = 60 seconds.

3 minutes x 60 seconds = 180 seconds.

180 seconds / 20 = 9

25 liters x 9 = 225

Total water in 3 minutes = 225 liters

7 0
3 years ago
Read 2 more answers
Ill give brainliest pls
Alona [7]

The answer is 207.

Search up the site Mathaway. It gives you answers.

6 0
3 years ago
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