F(x) = (1/2)x + 4
Plug y in for f(x).
y = (1/2)x + 4
Swap x and y.
x = (1/2)y + 4
Solve the equation for y =.
Subtract 4 from both sides.
x - 4 = (1/2)y
Multiply each term 2.
2x - 8 = y
Plug f^-1(x) in for y.
f^-1(x) = 2x - 8
f^-1(4) = 2(4) - 8
f^-1(4) = 0
Find the distance of each trip:
68 km / 34 trips = 2 km per trip
Divide total distance by distance per trip:
348 km / 2 km per trip = 174 trips
Answer: 174 trips
7 over 32 you cant simplify it
M∠ADB + m∠BDC = m∠ADC [<span>angle addition postulate]
x + x + 10 = 60
2x + 10 = 60
2x = 60 - 10
2x = 50
x = 50/2
x = 25
a
m</span>∠ADB = x = 25°
b
m∠BDC = x + 10 = 25 + 10 = 35°
m = (y2-y1)/(x2-x1)
m = (6-4)/(4-0)
m = 2/4
y = mx + c
6 = (2/4)(4) + c
c = 4
Thus, the equation is y = (2/4)x +4