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Anastasy [175]
3 years ago
6

Some students prepare 3 diffrerent snacks. They make 1/8 pound bags of nut mix, 1/4 pound bags of cherries, and 1/6 pound bags o

f dried fruit. If they buy 3 pounds of nut mix, 5 pounds of cherries, and 4 pounds of dried fruit,how many of each type of snack bag will they be able to make?
Mathematics
1 answer:
larisa86 [58]3 years ago
8 0

Answer: They made 24 snack bags of nut mix, 20 snack bags of cherries and 24 snack bags of dried fruit.

Step-by-step explanation:

They make 1/8 pound bags of nut mix. If they buy 3 pounds of nut mix, it means that the number of snack bags of but mix that they made is

3 /(1/8) = 3/0.125 = 24

They make 1/4 pound bags of cherries. If they bought 5 pounds of cherries, it means that the number of snack bags of cherries that they made is

5 /(1/4) = 5/0.25 = 20

They make 1/6 pound bags of dried fruit. If they bought 4 pounds of dried fruit, it means that the number of snack bags of dried fruit that they made is

4 /(1/6) = 24

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On a school trip to a theme park, 4 busses each carry 70 students.
DanielleElmas [232]

Answer:

165 Students Have No Made Plans For Lunch.

Step-by-step explanation:

According To the Question,

  • Given,On a school trip to a theme park, 4 busses each carry 70 students Then Total Number Of Students on a trip is 70×4=280 Students.
  • And,35% of the students are bringing their own lunch. Thus,35% Of 280 Students is 98 Students. Then Remaining 182 Students not bring their own lunch.

Now, 17 of the students are buying lunch when they get to the theme park. Thus students Who have not made plans for lunch is 182-17⇒165Students

7 0
3 years ago
The mayor of a town has proposed a plan for the annexation of an adjoining community. A political study took a sample of 900 vot
Stells [14]

Answer:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

Step-by-step explanation:

Information given

n=900 represent the random sample selected

\hat p=0.75 estimated proportion of residents favored annexation

p_o=0.72 is the value that we want to test

represent the significance level

z would represent the statistic

p_v represent the p value

Hypothesis to test

The political strategist wants to test the claim that the percentage of residents who favor annexation is above 72%.:  

Null hypothesis:p\leq 0.72  

Alternative hypothesis:p > 0.72  

The statistic for this case is given by:

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

Replacing the data given we got:

z=\frac{0.75 -0.72}{\sqrt{\frac{0.72(1-0.72)}{900}}}=2.00  

Now we can calculate the p value. Since is a bilateral test the p value would be:  

p_v= P(Z>2) =0.0228

Since the p value is lower than the significance level of 0.05 we have enough evidence to conclude that the true proportion of residents favored annexation is higher than 0.72 or 72%

3 0
3 years ago
Which expression is equivalent to 8(u + 3)?
Korolek [52]

Answer:

<h2>8(u + 3) = 8u + 24</h2>

Step-by-step explanation:

8(u+3)\qquad\text{use the distributive property}\ a(b+c)=ab+ac\\\\=(8)(u)+(8)(3)=8u+24

5 0
3 years ago
I guess this is question that im confused about :]​
andrew11 [14]

Answer:

124cm.³

Step-by-step explanation:

V = whl

You will do this: [2][3][8] + [3][4][5]. After finding the volume of both prisms, add them up.

I hope this helps, and as always, I am joyous to assist anyone.

4 0
3 years ago
Please help with math and please show your work will give brainliest
Burka [1]

Answer:

The Elimination Method is based on the Addition Property of Equality. The Addition Property of Equality says that when you add the same quantity to both sides of an equation, you still have equality. We will extend the Addition Property of Equality to say that when you add equal quantities to both sides of an equation, the results are equal.

For any expressions a, b, c, and d,

if  and  then a=bc=da+c=b+d

To solve a system of equations by elimination, we start with both equations in standard form. Then we decide which variable will be easiest to eliminate. How do we decide? We want to have the coefficients of one variable be opposites, so that we can add the equations together and eliminate that variable.

Notice how that works when we add these two equations together:

3x+y=52x−y=0–––––––––––5x=5

The y’s add to zero and we have one equation with one variable.

Let’s try another one:

{x+4y=22x+5y=−2(5.3.3)

This time we don’t see a variable that can be immediately eliminated if we add the equations.

But if we multiply the first equation by −2, we will make the coefficients of x opposites. We must multiply every term on both sides of the equation by −2.

This figure shows two equations. The first is negative 2 times x plus 4y in parentheses equals negative 2 times 2. The second is 2x + 5y = negative 2. This figure shows two equations. The first is negative 2x minus 8y = negative 4. The second is 2x + 5y = -negative 2.

Now we see that the coefficients of the x terms are opposites, so x will be eliminated when we add these two equations.

Add the equations yourself—the result should be −3y = −6. And that looks easy to solve, doesn’t it? Here is what it would look like.

This figure shows two equations being added together. The first is negative 2x – 8y = −4 and 2x plus 5y = negative 2. The answer is negative 3y = negative 6.

We’ll do one more:

{4x−3y=103x+5y=−7

It doesn’t appear that we can get the coefficients of one variable to be opposites by multiplying one of the equations by a constant, unless we use fractions. So instead, we’ll have to multiply both equations by a constant.

We can make the coefficients of x be opposites if we multiply the first equation by 3 and the second by −4, so we get 12x and −12x.

This figure shows two equations. The first is 3 times 4x minus 3y in parentheses equals 3 times 10. The second is negative 4 times 3x plus 5y in parentheses equals negative 4 times negative 7.

This gives us these two new equations:

{12x−9y−12x−20y=30=28

When we add these equations,

\[{12x−9y=30−12x−20y=28–––––––––––––––––−29y=58

\]

the x’s are eliminated and we just have −29y = 58.

Once we get an equation with just one variable, we solve it. Then we substitute that value into one of the original equations to solve for the remaining variable. And, as always, we check our answer to make sure it is a solution to both of the original equations.

Now we’ll see how to use elimination to solve the same system of equations we solved by graphing and by substitution

Step-by-step explanation:

Here is some examples

4 0
2 years ago
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