Answer:
B, C, D, maybe A
Step-by-step explanation:
The parent function, here is
f(x) = x² which is upward opening parabola.
In order to get a graph of f(x) = x²-1, shift the parent function, f(x) = x² by +1 unit downward. This is the transformation.
3x^2-18x+24
3(x^2-6x+8)
3(x-4)(x-2)
Thank you for posting the figure. Without it, I would have thought the parabola has a vertical axis.
For a parabola with a horizontal axis (as in this case), the equation of the parabola is
f(y)=a(y-k)^2+h
where (h,k) is the vertex.
Substituting (h,k)=(2,-4),
f(y)=a(y+4)^2+2...................(1)
as the equation of the parabola, with the value of "a" yet unknown.
Since we are given that the parabola passes through the point (-3,-3), we can substitute the corresponding x,y values in (1) to solve for a.
f(y)=-3=a(-3+4)^2+2
solve for a
a=(-3-2)/(1^2)=-5
So the equation of the parabola is f(y)=-5(y+4)^2+2
Answer:
10
Step-by-step explanation:
LN = 4 + x - 8 = x - 4
LS = 3 + x - 5 = x - 2
By intersecting secants theorem:
