She has 52 card all together so she has a probability of drawing on the first draw 4 L's or R's because their are two sets of alphabet cards. So that is 4/52 or 1/13 to the lowest term. Second turn she only has 51 cards to draw from and still has 4 L's and R's so that would be 4/51 and on the third try she has only 50 cards left so that would be 4/50 or 2/25 to the lowest term. Now multiply all three factions 1/13 x 4/51 x 2/25 = 8/16575 meaning out of the three draws she has a probability of getting a L or R, 8 out of 16575 each draw.
I think the answer is A because the data is skewed to the right
The median (middle) isn't 10, it's 8
The interquartile range (IQR) is 7 not 6 because you have to subtract the first and third quartile 13 - 6 = 7 not 6
Hope this helps! ;)
For number 3 add all the numbers and divide how numbers you have
Answer:
Step-by-step explanation :Answer
To chance an improper fraction into a mixed number first divide the numerator by the denominator
Example 11/5 divide 11 by 5 and you get 2.2 that means that 5 goes into 11 twice with some leftover which means the answer is going to be 2 plus a fraction
To get the fraction you multiply the denominator by the whole number you found (5*2) and subtract the numerator by that new number
5*2=10 11-10=1
Your new fraction is now 2 1/5
