Since we’ve been given a ratio, 3:8, we can convert that into a fraction and form an equation from it:
= 
The reason the numerator on the second fraction is 27/3 is because the team scored 27 points, not 27 baskets.
Simplify (Also replace the ? with an unknown variable):
= 
Cross multiply:
3*n = 9*8
Simplify:
3n = 72
Divide both sides by 3:
n = 24
The team had 33 three point tries, 9 successes, and 24 fails.
-T.B.
Answer:
The area is 72 cm².
Step-by-step explanation:
Since it is equivalent triangle
h = b
so,
b + b + b (since all sides are equal)= 36 cm
3b = 36 cm
or, b = 36/3
so, b = 12 cm
so
area of triangle = (1/2)×b×h
= (1/2)×12cm×12cm
= 6cm × 12cm
= 72 cm²
Answer:
4322 ft^2
Step-by-step explanation:
First, we need a formula. The formula is (50*110) - (3.14*18^2) - (4*40). The answer is 4322 ft^2 (This is the rounded answer)
Answer: There are 32 pints of first type and 128 pints of second type in mixture.
Step-by-step explanation:
Since we have given that
Percentage of pure fruit juice in first type = 60%
Percentage of pure fruit juice in second type = 85%
Percentage of pure fruit juice in mixture = 80%
We will use "Mixture and Allegation" to find the ratio of first and second type in mixture:
First type Second type
60% 85%
80%
------------------------------------------------------------------------
85-80 : 80-60
5% : 20%
1 : 4
so, the ratio of first and second type is 1:4.
Total number of pints of mixture = 160
Number of pints of mixture of first type in mixture is given by

Number of pints of mixture of second type in mixture is given by

Hence, there are 32 pints of first type and 128 pints of second type in mixture.
In the research, the distribution is described by its shape. If there are more higher values than lower values, the distribution is skewed left.
<h3>How to illustrate the research?</h3>
It should be noted that when the distribution of data is skewed to the <u>left</u>, the mean is less than the median.
The distribution can be described by its center. If the distribution is skewed left or right, the <u>median</u> is an accurate measure of center.
The distribution can be described by its spread. If the data set does not have an outlier, the interquartile range is an accurate measure of spread.
Learn more about research on:
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