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Snowcat [4.5K]
3 years ago
14

A figure skater begins spinning counterclock-

Physics
1 answer:
Lelu [443]3 years ago
3 0

Answer:

The average angular acceleration of the skater is <u>0.98 rad/s²</u>.

Explanation:

Given:

Initial angular speed of the skater is, \omega_i=3.27\ rad/s

Final angular speed of the skater is, \omega_f=7.77\ rad/s

Time interval for the change is, t=4.6\ s

We know that, average angular acceleration is given as the ratio of change of angular speed and the time interval.

Therefore, the average angular acceleration is given as:

\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\\\alpha =\dfrac{7.77-3.27}{4.6}\\\\\alpha=\dfrac{4.5}{4.6}\\\\\alpha=0.98\ rad/s^2

Hence, the average angular acceleration of the skater is 0.98 rad/s².

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What can pressure be measured by?
SOVA2 [1]
'Pressure' is  (force) / (area).

The only choice with those units is #1 .
5 0
4 years ago
6. As the sky diver's fall the______energy is converted into _______.
notka56 [123]

Answer:  B

D makes no sense because energy is created so we can remove that. C also makes no sense because if energy is not created how did it get destroyed if there's no energy in the first place. This leaves us with a and B the correct answer is B because energy is created and cannot be destroyed.

3 0
3 years ago
(a) A 2.00-µF capacitor is connected to a 18.0-V battery. How much energy is stored in the capacitor?
marshall27 [118]
<h2>Answer:</h2>

1.8 x 10⁻⁵J

<h2>Explanation:</h2>

The energy (E) stored in a capacitor of capacitance, C,  when a voltage, V, is supplied is given by;

E = \frac{1}{2} x C x V²              -------------------(i)

Now, from the question;

C = 2.00μF = 2.00 x 10⁻⁶F

V = 18.0V

Substitute these values into equation (i) as follows;

E = \frac{1}{2} x 2.00 x 10⁻⁶ x 18.0

E = 1.8 x 10⁻⁵J

Therefore, the quantity of energy stored in the capacitor is 1.8 x 10⁻⁵J

8 0
4 years ago
Read 2 more answers
How much energy is needed to change the speed of a 1600 kg sport utility vehicle from 15.0 m/s to 40.0 m/s?
podryga [215]

Answer:

Energy needed = 1100 kJ

Explanation:

Energy needed = Change in kinetic energy

Initial velocity = 15 m/s

Mass, m = 1600 kg

\texttt{Initial kinetic energy = }\frac{1}{2}mv^2=0.5\times 1600\times 15^2=180000J

Final velocity = 40 m/s

\texttt{Final kinetic energy = }\frac{1}{2}mv^2=0.5\times 1600\times 40^2=1280000J

Energy needed = Change in kinetic energy = 1280000-180000 = 1100000J

Energy needed = 1100 kJ

4 0
3 years ago
A projectile is launched horizontally from a height of 8.0 m. The projectile travels 6.5 m before hitting the ground.
lozanna [386]
You can find

1) time to hit the ground
2) initial velocity
3) speed when it hits the ground

Equations

Vx = Vxo

x = Vx * t

Vy = Vyo + gt

Vyo = 0

Vy = gt

y = yo - Vyo - gt^2 / 2

=> yo - y = gt^2 / 2

1) time to hit the ground

=> 8.0 = g t^2 / 2 => t^2 = 8.0m * 2 / 9.81 m/s^2 = 1.631 s^2

=> t = √1.631 s^2 = 1.28 s

2) initial velocity

Vxo = x / t = 6.5m / 1.28s = 5.08 m/s

3) speed when it  hits the ground

Vy = g*t = 9.81 m/s * 1.28s = 12.56 m/s

V^2 = Vy^2 + Vx^2 = (12.56 m/s)^2 + (5.08 m/s)^2 = 183.56 m^2 / s^2

=> V = √ (183.56 m^2 / s^2) = 13.55 m/s
7 0
3 years ago
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