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3 years ago

Help can’t find the answer no where

Physics

1 answer:

katen-ka-za [31]3 years ago

5 0

i'm stuck on that question also

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Fill in the blank

aliina [53]

Answer:

hypothesis

Explanation:

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3 years ago

A number of conditions are required for a population to be in Hardy-Weinberg equilibrium. Which of the following are correct des

S_A_V [24]

Answer: A, B, F

Explanation:

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2 years ago

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An object in motion will stay in motion unless acted upon by what type of force

coldgirl [10]

An object will stay in motion unless acted upon by an UNBALANCED force.

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2 years ago

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a bullet with a mass of 4.0g and a speed of 650m/s is fired at a block of wood with a mass of 0.095kg. the block rests on a fric

n200080 [17]

Part a)

Here in this we can use momentum conservation as there is no external force on it

$m_1v_{1i} + m_2v_{2i} = m_1v_{1f} +m_2v_{2f}$

here we know that

$m_1 = 0.004 kg$

$v_{1i} = 650 m/s$

$m_2 = 0.095$

$v_{2i} = 0$

$v_{2f} = 23 m/s$

now by above equation

$0.004*650 + 0.095* 0 = 0.004*v + 0.095*23$

$2.6 + 0 = 0.004*v + 2.185$

$v = 103.75 m/s$

Part b)

Final kinetic energy of the system

$KE_f = \frac{1}{2}m_1v_{1f}^2 + \frac{1}{2}m_2v_{2f}^2$

$KE_f = \frac{1}{2}*0.004*(103.75^2) + \frac{1}{2}*(0.095)*23^2$

$KE_f = 46.65 J$

Initial Kinetic energy of the system will be

$KE_f = \frac{1}{2}m_1v_{1i}^2 + \frac{1}{2}m_2v_{2i}^2$

$KE_f = \frac{1}{2}*0.004*(650^2) + \frac{1}{2}*(0.095)*0^2$

$KE_f = 845 J$

So here kinetic energy is decreased for this system

final energy is less than initial energy

6 0

2 years ago

Suppose a truck has a momentum of 40,120 kg • and a mass of 1,180 kg. What is the truck’s velocity?

gladu [14]

Answer:

The velocity of the truck is 34 m/s.

Explanation:

The momentum (p) of an object is the product of its mass (m) and its velocity (v) which can be written as:

p = mv

Here in this problem, we are given a truck which has a momentum of 40120 kg and a mass of 1180 kg and we are to find its velocity.

So substituting the given values in the above formula to find the velocity of the truck.

Truck's velocity = $\frac{40120}{1180}$ = 34 m/s.

3 0

3 years ago