notice... a derivative is just the function for the slope
now, you're given the point 3,1, namely x = 3 and y = 1
to find the "m" or slope, use that derivative, namely
that'd give you a value for the slope
to get the tangent line at that point, simply plug in the provided values
in the point-slope form
and then you solve it for "y", I gather you don't have to, but that'd be the equation of the tangent line at 3,1
Answer:
356.82
Step-by-step explanation:
Answer:
9
Step-by-step explanation:
The first thing we shall be doing here is substituting f(x) into g(x).
Mathematically, that would be written as g(f(x))
= 2(4x-3)-1 = 8x -6 -1 = 8x - 7
Now we shall find g(f(2)) by substituting 2 into the expression above.
Mathematically, that would be 8(2) -7 = 16-7 = 9