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guajiro [1.7K]
3 years ago
11

Simplify the expression (k^2)^4

Mathematics
2 answers:
Andrews [41]3 years ago
7 0
It would be K^{8}
Blababa [14]3 years ago
3 0
I would do it this way:
((k2)×(k2))2
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Answer: \frac{(x-4)^2}{196} +\frac{(y-1)^1}{169} =1

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You first need to determine if the ellipse is horizontal or vertical, which can be found by the length of the major axis.

The vertices are at (18,1) and (-10,1). The distance is 28 units.  (horiz)

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\frac{(x-h)^2}{a^2} +\frac{(y-k)^2}{b^2} =1 where (h,k) are the coordinates of the center.

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The minor axis is 2b, so b would e 26/2=13 squared: 169

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\frac{(x-4)^2}{196} +\frac{(y-1)^1}{169} =1

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