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larisa [96]
4 years ago
12

Complete this item

Mathematics
1 answer:
Trava [24]4 years ago
7 0

Step-by-step explanation:

(39×x^5×z^4)^0 ×18×x^2×y

1×18×x^2×y

18x^2y

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What is the image of the point (-5,-7) after a rotation of 270 counterclockwise about the origin
Softa [21]

Answer:

Your answer will be (-5,7).

Step-by-step explanation:

4 0
4 years ago
Write in standard form y=2(x-1)^2+6
vlabodo [156]

Answer:

Y=2x+2

Step-by-step explanation:

Im not 100% sure this is correct but what I did was

Y=2(x-1)^2+6

2(x-1) = 2x -2

Y=2x -2^2 +6

Y=2x -4 + 6

-4 + 6 = 2

So y=2x+2 (y=mx+b)

I hope this helps you

4 0
3 years ago
Please help need asap
MrRissso [65]

Answer:

b and e.

Step-by-step explanation:

You will find this by solving each equation for 15b (get 15b by itself)

4 0
3 years ago
How many points are needed to determine a straight line?
GuDViN [60]

Answer:

2

Step-by-step explanation:

You only need two points to create a line...

8 0
3 years ago
A sample of a radioactive substance decayed to 97% of its original amount after a year. (Round your answers to two decimal place
Alborosie

Answer:

23 years

Step-by-step explanation:

Step 1: Calculate the rate constant (k) for the radioactive decay

A radioactive substance with initial concentration [A]₀ decays to 97% of its initial amount, that is, [A] = 0.97 [A]₀, after t = 1 year. Considering first-order kinetics, we can calculate the rate constant using the following expression.

ln [A]/[A]₀  = - k.t

k = ln [A]/[A]₀ / -t

k = ln 0.97 [A]₀/[A]₀ / -1 year

k = 0.03 year⁻¹

Step 2: Calculate the half-life of the substance

We will use the following expression.

t_{1/2} = ln2/ k = ln 2 / 0.03 year⁻¹ = 23 years

4 0
3 years ago
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