Alright so I'm coming up with this on the fly; you have the first six letters (a,b,c,d,e,f) and 0-9 and your ten numbers. calculate the amount of possible combinations for the letters by simply writing them down.
ab, ac, ad, ae, a f- five
bc, bd , be, bf- four
cd, ce, cf- three
de, df- two
ef,- one.
adding these all together gets a total of 15 for the letters. now the numbers
01, 02, 03, 04, 05, 06, 07, 08, 09- nine
12, 13, 14, 15, 16, 17, 18, 19- eight
23, 24, 25, 26, 27, 28, 29- seven
34, 35, 36, 37, 38, 39- six
45, 46, 47, 48, 49- five
56, 57, 58, 59- four
67, 68, 69- three
78, 79- two
89- one
added together with a total of 45 combinations.
alright so, 45 different number combinations and 15 letter combinations. multiplying 15 by 45 should tell you the total possible combinations for a two letter and two number serial-number
The answers are 
and 8 · 8 · 8
Explanation:
The volume of a cube or space a cube occupies is calculated by multiplying the length, height, and width. Additionally, because in a cube all sides are equal in length, the formula for volume is V= 
. According to this, if the side length is 8 inches the volume can be represented as 
or V= 8 · 8 · 8 because the symbol · represents multiplication. Also, this can be solved as V = 512 cubic inches. This makes the following options correct: and 8 · 8 · 8.
M=dc/dp=4/6=4/6=2/3
c(p)=2p/3 +b using (6,4)
4=2(6)/3+b
4=4+b, b=0 so
c(p)=2p/3
(the number of cherries needed as a function of the number of pies)
Answer:
(x+3)^2 + (y-7)^2 = 2^2
Step-by-step explanation:
Follow the standard form of a circle, (x-h)^2 + (y-k)^2 = r^2, given that (-3,7) is (h,k) and 2 is r.
Step-by-step explanation:
there 5^(n+1) + 5^(n+2) = 5^n x 5^1 + 5^n x 5^2 breaking them as x^(a+b) = x^a x x^b
then taking common 5^n from both terms
