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ivanzaharov [21]
3 years ago
5

A2 + 42 = 52 i’ve done this equation over and over and can’t get it correct

Mathematics
2 answers:
Dominik [7]3 years ago
5 0

Answer:

umm, a=3 I believe?

Step-by-step explanation:

4²=16, and 5²=25 so 25-16=9 and the square root of 9 is 3

taurus [48]3 years ago
4 0

Answer:

a = 3

Step-by-step explanation:

a^2 + 4^2 = 5^2

Step 1 square all exponents

a^2 + 16 = 25     4*4 = 16 and 5*5 = 25

Step 2 subtract 16 from both sides

a^2 +16 = 25

      -16    -16

a^2 = 9

Step 3 square root both sides

a = 3       square root of 9 is 3

Hope I helped!!

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im not sure wether to replace the minus signs with addition, so if you could help me that would be nice :) 1.2y+4.5-3.4y-6.3
Elenna [48]

Answer:

-2.2y - 1.8

Step-by-step explanation:

We are to simplify the expression:

1.2y + 4.5 - 3.4y - 6.3

Collect like terms:

1.2y - 3.4y + 4.5 - 6.3

Simplify:

-2.2y - 1.8

That is the answer.

6 0
3 years ago
What is the value of<br> 1: 7³<br> 2: 2⁶<br> 3: 4⁴
Veseljchak [2.6K]
1) 343
7 • 7 • 7 = 343

2) 64
2 • 2 • 2 • 2 • 2 • 2 = 64

3) 256
4 • 4 • 4 • 4 = 256
7 0
3 years ago
Read 2 more answers
Write equivalent expression for 7× + 4× + 3-1
Mazyrski [523]

Answer: you just flip it. It would be the opposite.

Step-by-step explanation:

When you flip it, what’s the difference? It’s still the same.

6 0
3 years ago
Find the least common denominator <img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7B9%7D%20%5Cfrac%7B8%7D%7B4%7D" id="TexFormul
MA_775_DIABLO [31]

Answer:

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Step-by-step explanation:

8 0
2 years ago
Construct a quadratic polynomial whose zeroes are negatives of the zeroes of the
sp2606 [1]

Given:

The given quadratic polynomial is :

x^2-x-12

To find:

The quadratic polynomial whose zeroes are negatives of the zeroes of the given polynomial.

Solution:

We have,

x^2-x-12

Equate the polynomial with 0 to find the zeroes.

x^2-x-12=0

Splitting the middle term, we get

x^2-4x+3x-12=0

x(x-4)+3(x-4)=0

(x+3)(x-4)=0

x=-3,4

The zeroes of the given polynomial are -3 and 4.

The zeroes of a quadratic polynomial are negatives of the zeroes of the given polynomial. So, the zeroes of the required polynomial are 3 and -4.

A quadratic polynomial is defined as:

x^2-(\text{Sum of zeroes})x+\text{Product of zeroes}

x^2-(3+(-4))x+(3)(-4)

x^2-(-1)x+(-12)

x^2+x-12

Therefore, the required polynomial is x^2+x-12.

4 0
3 years ago
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