Answer and Explanation:
Given data:
Distance (D) = 40 KM
Speed of light in the fiber =Distance/ speed of light in the fiber
a) Delay (P) = Distance/ speed of light in the fiber
= (40,000 Meters/2×108 m/s)
=( 40×103 Meters/2×108 m/s)
Propagation delay (P) = 0.0002 seconds or 200 microseconds
b)
if propagation delay is 0.0002 Seconds roundup trip time (RTT) will be 0.0004 Seconds or 400 micro Seconds
Essentially since transmission times and returning ACKs are insignificant all we really need is a value slightly greater than 0.0004 seconds for our timeout value.
c)
The obvious reasons would be if the data frame was lost, or if the ACK was lost. Other possibilities include extremely slow processing on the receive side (late ACK).
Or Extremely Slow Processing of the ACK after it is received back at the send side.
Step 1. Click the address bar at the top of your Google Chrome window, type "About: cache" into the box and press "Enter." A page will appear with a list of cached files and their addresses.
Step 2. Press the "Ctrl" and "F" keys on your keyboard at the same time to open the find bar.
Step 3. Type part of the name or address of a cached file into the find box and press "Enter" to find it. Continue pressing "Enter" to page through any matching results.
Step 4. Select the full address of the cached file on the page with your mouse and press "Ctrl" and "C" at the same time to copy the address.
Step 5. Click the address bar, press "Ctrl" and "V" at the same time to paste the address and press "Enter" to load the file. Chrome loads the file from the cache.
Step 6. Right-click the image, page or script and select "Save As" to save the cached file to your computer.
The limitation of computer are:
- No self-intelligence
- No feeling
- No learning power
- Dependency
A. Assets increase, and liabilities decrease.
