Solution :
int f(int x){
;
}*/
int f(
){
int stack[2] = {
};
;
;
;
R1 = R1 * C; /*R1 =
*/
;
* R2; /* R0 = bx */
; /*R0 =
*/
;
; /*R0 = a+bx+cx^2 */
}
/*
int s=0;
{
;)
*/
AREA SumSquares, code, readWrite
ENTRY
;loop
MOV r1, #0 ; s = 0
Loop
;calculate i*i
;s = s+ i*i
, #1 ; i = i+1
,#10 ; test for end
Loop ;
END
Newer, or current versions of Windows from XP to 10 use the NTFS file system. The file system supports up to 255 characters in a file name. The total path length supports up to 30,000 characters.
Answer:
The output of this question is 21. As show in the image
The explanation is given in below
Explanation:
Let first write the question
C=1
sum = 0
while(C<10):
C=C+3
sum=sum + C
print(sum)
Now Focus on
while(C<10):
C=C+3
sum=sum + C
The value of C is initially 1
C=1+3
Sum= 0+4
In second loop the value of C will become 4
c=4+3
sum=4+7
In third loop the value of C will be 7
c=7+3
sum=11+10
so the answer is 11+10=21